Vigenere table in 2d array
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Thread: Vigenere table in 2d array

  1. #1
    Join Date
    Mar 2012
    Posts
    2

    Vigenere table in 2d array

    So I've been trying to make a vigenere 2d array my first try was using this:
    Code:
                char[][] table = new char [25][];
                int n = 0;
                int m = 0;
                int i;
                int diff;
                for (i = 65; i == 91; i++)
                {
                    if (n != 0)
                    {
                        i = i + n;
                        if (i > 90)
                        {
                            diff = i - 90;
                            i = 64 + diff;
                        }
                    }
    
                    table[n][m] = Convert.ToChar(i);
                    m++;
                    if (m == 26 && n < 26)
                    {
                        n++;
                        i = 65;
                    }
                }
    but the array still had null values after this

    so I decided to try a more simple method:
    Code:
                char [] alphabet = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
                char[][] table = new char [25][];
                int n = 0;
                int m = 0;
                int i = 0 ;
                int diff;
    
                while (m != 26)
                {
                    if (m > 0)
                    {
                        i = i + m;
                        if (i > 25)
                        {
                            diff = i - 25;
                            i = 0 + diff;
                        }
                    }
                    table[m][n] = alphabet[i];
                    n++;
                    i++;
                    if (n == 25)
                    {
                        n = 0;
                        m++;
                        i = 0;
                    }
                    }
    but it still did not work.
    If you can help me fix any of these it would be great!

  2. #2
    Join Date
    Feb 2011
    Location
    United States
    Posts
    1,006

    Re: Vigenere table in 2d array

    How about:

    Code:
    char [] alphabet = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
    
    char[][] table = new char [alphabet.Length][];
    for(int r = 0; r < alphabet.Length; r++)
    {
        table[r] = new char[alphabet.Length];
        
        for(int c = 0; c < alphabet.Length; c++)
        {
            table[r][c] = alphabet[(r+c) &#37; alphabet.Length];
        }
    }
    Last edited by BioPhysEngr; March 4th, 2012 at 03:32 PM. Reason: replaced tabs with four spaces
    Best Regards,

    BioPhysEngr
    http://blog.biophysengr.net
    --
    All advice is offered in good faith only. You are ultimately responsible for effects of your programs and the integrity of the machines they run on.

  3. #3
    Join Date
    Mar 2012
    Posts
    2

    Re: Vigenere table in 2d array

    wow, thank you!

    is there any good tutorial or book I could get for more info on how to work with different dimension arrays?

    because I encounter problems further in my work.


    here I'm trying to cipher the entered text which is in textBox1 (text1) by using letters entered for the key (key).
    Code:
                string derp1 = textBox1.Text;            
                int k = 0;
                int len = derp1.Length;
                char[] text1 = new char[len];
                text1 = derp1.ToCharArray(); // user text
                string derp2 = textBox2.Text;
                int len2 = derp2.Length;
                char[] key = new char[len2];
                key = derp2.ToCharArray(); // user key
                char[] code = new char[len];
                i = 0;
    
                while (i != len)
                {
                    if (table[n][m] == key[k]) //looking for the key letter in the vigenere table
                    {
                        if (table[n][m] == text1[i]) //looking for the according letter in the row where the key was found 
                        {
                            code[i] = table[m][n]; //saving the ciphered text into code[i]
                            k++;
                            i++;
                            n = 0;
                            m = 0;
                            if (k > len2) //checking if we got to the last letter of the entered key to restart it
                            {
                                k = 0;
                            }
    
                        }
                        else
                            n++;
                    }
                    m++;
                }
            }

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