Counting words in each sentence using C#

[fozki]

Hello, just wondering how to count words up to a point (for example, a period)?

For example, given the string:

That was a fun movie. I want to watch it again. We should sometime.

What code would you need to count the words in each individual sentence (that is, 5, 6 then 3 using the above example string)?

Thank you, I've been looking for a solution to this problem but it's got the better of me

[Erendar]

Awnser this question, how do you see with your eyes that it's the end of a word. What did your eyes did ?
Hint for programming : loop, if

[HanneSThEGreaT]

You'll need to do some string manipulation. What you actually need here is to look up String.Split and String.Substring and String.LastIndexOf - Just naming a few that immediately pops into my head.

[HanneSThEGreaT]

OK, this is a bit sloppy, but it should give you a good principle to start with :

        private void button1_Click(object sender, EventArgs e)
        {
            string strInput = textBox1.Text;

            string[] arrInputDots;
            string[] arrInputSpaces;
            int intWordCounter;
            int intTotalWords = 0;
            int intTempCount = 0;

            arrInputDots = strInput.Split('.');

                foreach (string strElement in arrInputDots)

	            {
                    intTempCount += 1;

                    arrInputSpaces = strElement.Split(' ');
                    intWordCounter = arrInputSpaces.Length;
                   
                    intTotalWords += intWordCounter;
                    if (intTempCount == 2)
                    {
                        intWordCounter -= 1;
                        intTotalWords -= 1;
                    }

                    MessageBox.Show("Sentence Contains " + intWordCounter.ToString() + " Words");
	            }

                MessageBox.Show("Total Words in all sentences: " + intTotalWords.ToString());
        }

Hope this helps!

[BioPhysEngr]

You probably also want to use string.Split(string, StringSplitOptions) giving StringSplitOptions.RemoveEmptyEntries as the second argument.

You might also think about canonicalizing your string to contain only a restricted character set (namely "A-Za-z0-9. "). That should avoid any problems if non-space whitespace characters are present.

[B3ertrnd]

Hey,
I'm just learning to program, so I've tried to add some of the cool stuff that I've learned into this (LINQ, Yield, etc)


class Program
{
static void Main(string[] args)
{
const string paragraph = "Sentence one. Sentence two contains some more words. Sentence three; thinking.";

foreach (KeyValuePair<string, uint> sentence in GetWords(paragraph))
{
Console.WriteLine(string.Format("sentence: [{0}] \n words: {1}", sentence.Key, sentence.Value));
}

Console.ReadLine();
}

public static IEnumerable<KeyValuePair<string, uint>> GetWords(string Paragraph)
{
//add some exceptions
IList<string> exceptions = new List<string>();
exceptions.Add(",");
exceptions.Add(";");
exceptions.Add(" ");
exceptions.Add(".");
exceptions.Add(string.Empty);

foreach (string sentence in Paragraph.Split('.'))
{
yield return new KeyValuePair<string, uint>(sentence, (uint)sentence.Split(' ').Where
(i => !exceptions.Contains(i)).Count());
}

}

}

[B3ertrnd]

Apologies, with the correct 'code' tag, for readability.
I'll delete the last reply when an admin gives me those rights!

class Program
{
static void Main(string[] args)
{
const string paragraph = "Sentence one. Sentence two contains some more words. Sentence three; thinking.";

foreach (KeyValuePair<string, uint> sentence in GetWords(paragraph))
{
Console.WriteLine(string.Format("sentence: [{0}] \n words: {1}", sentence.Key, sentence.Value));
}

Console.ReadLine();
}

public static IEnumerable<KeyValuePair<string, uint>> GetWords(string Paragraph)
{
//add some exceptions
IList<string> exceptions = new List<string>();
exceptions.Add(",");
exceptions.Add(";");
exceptions.Add(" ");
exceptions.Add(".");
exceptions.Add(string.Empty);

foreach (string sentence in Paragraph.Split('.'))
{
yield return new KeyValuePair<string, uint>(sentence, (uint)sentence.Split(' ').Where
(i => !exceptions.Contains(i)).Count());
}

}

}

[Deranged]

Here is my method of doing it, console application so that you can enter whatever sentence you want. (I do not like String.Split)

That was a fun movie. I want to watch it again. We should sometime.

OUTPUTS:
Sentence 1 = 5 words.
Sentence 2 = 7 words.
Sentence 3 = 4 words.
Press any key to continue...

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace TestApplications
{
    class Program
    {
        static void Main(string[] args)
        {
            if (args.Length == 1 && args[0] == "/?")
            {
                Console.WriteLine("SYNTAX: TestApplications <Sentence>");
#if DEBUG
                Pause();
#endif
                return;
            }
            if (args.Length < 1)
            {
                Console.WriteLine("Invalid Syntax! /? for help.");
#if DEBUG
                Pause();
#endif
                return;
            }

            string sentence = args[0];

            if (String.IsNullOrEmpty(sentence))
            {
                Console.WriteLine("String is empty!");
                return;
            }

            foreach (List<int> count in ParseSentence(sentence))
            {
                Console.WriteLine(String.Format("Sentence {0} = {1} words.", count[0], count[1]));
            }

#if DEBUG
            Pause();
#endif

        }
        private static IEnumerable<List<int>> ParseSentence(string input)
        {
            int wordCount = 0;
            int sentenceCount = 0;
            List<int> ret = new List<int>();

            for (int i = 0; i < input.Length; i++)
            {
                if (input[i] == ' ') //End of word
                {
                    ++wordCount;
                    continue;
                }
                if (input[i] == '.') //End of sentence
                {
                    ++wordCount; //Period should be at the end of a word...
                    ++sentenceCount;
                    ret.Add(sentenceCount);
                    ret.Add(wordCount);
                    yield return ret;

                    ret = new List<int>();
                    wordCount = 0;
                }
            }
        }
        private static void Pause()
        {
            Console.WriteLine("Press any key to continue...");
            Console.ReadKey(true);
        }
    }
}