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August 29th, 2012, 09:24 PM
#1
HEX Overflow error 6
I have encountered overflow error 6 with this code in VB 6:
step9 = Hex((CLng("&H" & "e753") * clng("&H" & "f010"))Mod (2^16+1))
cipher=step9
Help please!
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August 30th, 2012, 04:58 AM
#2
Re: HEX Overflow error 6
Shouldn't it be Mod (2^16-1)
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September 6th, 2012, 07:52 AM
#3
Re: HEX Overflow error 6
don't know what you want to do but 59219 * 61456 is too much for a Long
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