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  1. #1
    Join Date
    Aug 2012
    Posts
    1

    HEX Overflow error 6

    I have encountered overflow error 6 with this code in VB 6:

    step9 = Hex((CLng("&H" & "e753") * clng("&H" & "f010"))Mod (2^16+1))
    cipher=step9

    Help please!

  2. #2
    Join Date
    Jun 2005
    Location
    JHB South Africa
    Posts
    3,772

    Re: HEX Overflow error 6

    Shouldn't it be Mod (2^16-1)
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  3. #3
    Join Date
    Sep 2012
    Posts
    7

    Re: HEX Overflow error 6

    don't know what you want to do but 59219 * 61456 is too much for a Long

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