StringGrid,Memo
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  1. #1
    Join Date
    Mar 2011
    Location
    Greece
    Posts
    26

    StringGrid,Memo

    Goodmorning
    I want some help. I have a stringgrid with some values inside.

    1 8,2
    2 8,3
    3 8,7
    4 10,1

    So my question is how i can take these fields to a memo component...any ideas;;;;; is it simple;;;;;; because i want to print it after...can i print it straight from the stringgrid my values to a printer

  2. #2
    Join Date
    Nov 2012
    Location
    Kolkata, WestBengal, India
    Posts
    15

    Re: StringGrid,Memo

    Yes you can do that using similar code to this -
    Code:
      int k=0;
      for (int rowint=0;rowint<StringGrid1->RowCount;rowint++)
      {
        for (int colint=0;colint<StringGrid1->ColCount ;colint++)
        {
           Memo1->Lines->Strings[k++] = StringGrid1->Cells[rowint][colint];
        }
      }
    or, as you have mentioned that you will print the stringgrid values lateron,
    you can use - TextOut() or Drawtext to print on a TPrinter->Canvas.

    Suppose your StringGrid has 3 column, px[0], px[1] and px[2] are 3 values to determine x position of printer output, py0 is top position, py is y position and stepy is line distance:

    Code:
      for(int i=0;i<StringGrid1->RowCount;i++)
      { 
        py=py0 + i*stepy; 
        for(int j=0;j<=3;j++)
        { 
          Printer()->Canvas->TextOut(px[j],py,StringGrid1->Cells[j][i]); 
        }
    I am not a hard core fan of StringGrid, but have a good intension to help you out.
    Hope this helps.

  3. #3
    Join Date
    Mar 2011
    Location
    Greece
    Posts
    26

    Re: StringGrid,Memo

    Hi
    you help little and thank you but still some little problems

    for this:

    int k=0;
    for (int rowint=0;rowint<StringGrid1->RowCount;rowint++)
    {
    for (int colint=0;colint<StringGrid1->ColCount ;colint++)
    {
    Memo1->Lines->Strings[k++] = StringGrid1->Cells[rowint][colint];
    }
    }

    I took only the first column and not the second. So need to fix the code little more

    Code:

    for(int i=0;i<StringGrid1->RowCount;i++)
    {
    py=py0 + i*stepy;
    for(int j=0;j<=3;j++)
    {
    Printer()->Canvas->TextOut(px[j],py,StringGrid1->Cells[j][i]);
    }

    for that i have only 2 dimensions so we can fix it more simple.. any ideas

  4. #4
    Join Date
    Nov 2012
    Location
    Kolkata, WestBengal, India
    Posts
    15

    Re: StringGrid,Memo

    It was just an example, you could have modified it according to your need;
    anyway, I have deleted some part of code to deal with the exact requirement you have here -

    "I took only the first column and not the second. So need to fix the code little more"
    So, the first one would be like this -
    Code:
      for (int rowint=0;rowint<StringGrid1->RowCount;rowint++)
      {
           //as you want only first column, I have hardcoded the Cells values to consider only [0] th/1st column.
           Memo1->Lines->Strings[rowint] = StringGrid1->Cells[rowint][0];
      }
    "for that i have only 2 dimensions so we can fix it more simple.. any ideas"
    So, the second one would be like this -
    Code:
      for(int i=0;i<StringGrid1->RowCount;i++)
      { 
        py=py0 + i*stepy; 
        //two columns - 0,1; so loop will go from j-0 to j<2
        for(int j=0;j<2;j++)
        { 
          Printer()->Canvas->TextOut(px[j],py,StringGrid1->Cells[j][i]); 
        }
      }
    Hope this time you will understand it more clearly.

    "Please put tags around your code to preserve indentation and make it more readable."

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