Storing 2D char array

[naildirt]

Hi, I am unable to understand why is the output for this shows me the address of the stored array.

int main()
{
size_t k= 0 ;
char t[3][100] = { "hi", "di", "fi" } ;
char s[3][100] ;
for (int r = 0 ; r < 3 ; r++)
{
size_t k = strlen (t[r]);
for ( int c = 0 ; c < k ; c++)
{


s[r][c] = t[r][c] ;
// cout << s[r][c] ; // this works perfect to show me the output
}
}

cout << s[r][c] ;

}

[GCDEF]

You need to learn to use code tags.
You need to learn to use your debugger.
What is the value of r and c in your last cout statement?

[Paul McKenzie]

Hi, I am unable to understand why is the output

How can you get output from a program that cannot be compiled successfully? What compiler are you using (version and number)?

First, even if you add the missing headers, the code should not have compiled:

#include <iostream>
#include <cstring>

using namespace std;

int main()
{
    size_t k= 0 ;
    char t[3][100] = { "hi", "di", "fi" } ;
    char s[3][100] ;
    for (int r = 0 ; r < 3 ; r++)
    { 
       size_t k = strlen (t[r]); 
       for ( int c = 0 ; c < k ; c++)
       {
          s[r][c] = t[r][c] ;
       }
    }
    cout << s[r][c] ; // <--- How did this line compile??
}

This is not valid ANSI C++ code. The variables "r" and "c" are not available outside of where they were declared as loop counters. So how could you have created a program with incorrect C++ syntax?

for this shows me the address of the stored array.

For me, it shows nothing since no program was even created due to syntax errors.

Regards,

Paul McKenzie

[raju2001006]

Yes, exactly. The code will not get compiled.

Now, if you define 'r' and 'c' outside the first for loop, at this point it shouldn't show any specific values -
cout << s[r][c] ;
coz, at this point it will be out of the range of the array s - here the line will get resolved to -
cout << s[3][2] ; <== whcih yet not get assigned

Hope, my points are clear here...

[VictorN]

... here the line will get resolved to -
cout << s[3][2] ; <== whcih yet not get assigned

Hope, my points are clear here...

I have no idea why you need to output the value of some array element outside the loop, however, using 3 as the first index of array s is illegal: only indexes 0 to 2 are valid since this array has only 3 rows.

[raju2001006]

Technically speaking, s[3][2] is not illegal - it's just not good practice to use such invalid array counters.

You can actually assign something in s[3][2]; - but the Stack around s may get corrupted because of this.

use something like -
s[3][0]='R'
cout << s[3][0]; <<== you will surely get the value stored at s[3][0].