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Thread: help with overloading code

  1. #1
    Join Date
    Jan 2013

    help with overloading code

    Can anyone help me with overloading. I have a task that starts with 2 numbers being entered by the user. then it increases to three numbers entered then 4 . how can I get the user input then have the program automatically figure the average of the numbers entered. Please help

    import java.util.*;
    class FinalAverage	{
    	void Sum(int num1, int num2)
    		System.out.println("Sum of "+ num1 + " and " + num2+ " is " +(num1 + num2));
    	void Sum(int num1, int num2, int num3)
    		System.out.println("Sum of "+ num1 + " and " + num2+ " and " + num3+ " is " +(num1 + num2 + num3));
    		public static void main(String[] args) {
    			float average;
    			int count = 0, x,x2, sum = 0 ;
    			Average Sum1 = new Average();
    			Scanner input = new Scanner(;
    			try	{	
    				System.out.println("Enter first number to find the Average ");
    				x = input.nextInt();
    							System.out.println("Enter second number to find the Average ");
    					count = 1;
    					//x2 = input.nextInt();
    					Sum1.Sum (x,x);
    					Sum1.Sum(x, x,x);
    					sum = x + x;	
    		 		catch (NumberFormatException e)
    		 			System.out.println("You did not enter an integer, and an Error occured. Please enter an integer?");
    			average = (sum/count);
    			System.out.println("your average of the numbers entered equals......" + average);

  2. #2
    Join Date
    Jul 2005
    Currently in Mexico City

    Re: help with overloading code

    Wanna install linux on a vacuum cleaner. Could anyone tell me which distro sucks better?

    I had a nightmare last night. I was dreaming that Iím 64-bit and my blanket is 32-bit and I couldnít cover myself with it, so Iíve spent the whole night freezing. And in the morning I find that my blanket just had fallen off the bed. =S (from:

    //always looking for job opportunities in AU/NZ/US/CA/Europe :P

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  3. #3
    Join Date
    Aug 2011
    West Yorkshire, U.K.

    Re: help with overloading code

    Overloading means using the same method name but with different numbers and/or types of parameters.
        public double average(int first, int second) {
            double result = (first + second) / 2;
            return result;
        public double average(int first, int second, int third) {
            double result = (first + second + third) / 3;
            return result;
        public double average(int first, int second, int third, int fourth) {
            // Sure you can guess what goes here
    Then you can call the average() method with 2, 3 or 4 integer arguments and always get a double as the result.
    There comes a point where this gets excessive (e.g. with 5, 6, 7 or more integer arguments) - then it would be worth considering either using varargs (as suggested in the previous post) or passing the arguments as an array of integers.

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