Unique random numbers in an array

[f0rumh4x]

Below is my code for a program that is suppose to generate and display six unique random numbers (between 1 and 54). The issue seems to be in my check for duplicates. I know what I am doing wrong but can't seem to find a way to fix it. I think it is getting stuck in an endless loop because the way I have written it looks like it checks the first value against itself which will of course look like a duplicate everytime. I am relatively new to programming, but catch on quickly....just a point in the right direction would be of immense help. Thanks.

#include<iostream>
#include<ctime>
using namespace std;

//function prototype
int getRandNumb();

int main ()
{
   srand((unsigned)time(NULL));

   //declare array
   int randomNum[6];

   //declare variable
   int checkNum = 0;
	
   for (int x = 0; x < 6; x += 1)
   {
	   randomNum[x] = getRandNumb();

	   if (randomNum[x] == randomNum[0] || randomNum[1] || randomNum[2] || randomNum[3] ||randomNum[4] || randomNum[5])
		   x -= 1;
	   else
		   cout << randomNum[x] << endl;
   } //end for
   
   cin.get();
   return 0;
} //end of main function

//*****function definition(s)*****
int getRandNumb()
{
    return rand()%54 - 1 + 1;
} //end of getRandNumb function

[GCDEF]

	   if (randomNum[x] == randomNum[0] || randomNum[1] || randomNum[2] || randomNum[3] ||randomNum[4] || randomNum[5])

That's not how you write multiple conditions in C++. randomNum[1] is an expression by itself, so unless it's 0, the entire statement will always be true. The way you wrote the first check is the way you need to write them all.