is possible create a any type variable(1 variable that accept any type of values)?

[Cambalinho]

Now that you have a c++11 compiler, you might want to revisit where all this started - How can I convert write procedure to cout

http://forums.codeguru.com/showthrea...cedure-to-cout

and see my post #15 with the solution using variadic templates. As gcc 4.8.1 supports variadic templates, this code should compile and give you the write function you originally wanted without using the variant class - which I suspect is going to give more trouble than it's worth.

#include <iostream>
using namespace std;

void write()
{
   cout << " ";
}

template <typename A, typename ...B>
void write(A argHead, B... argTail)
{
   cout << argHead << " ";
   write(argTail...);
}


int main(void)
{
   write(1, 2, "qwerty", 4.45, "five", 6);
   return 0;
}

thanks.
now i'm doing the same for read(): but i get errors:

void read()
    {
        cin >> " ";
    }

    template <typename A, typename ...B>
        void read(A argHead, B... argTail)
        {
            cin >> argHead >> "";
            read(argTail...);
        }

don't forget theres these type of read too:

void read()
	{
		DWORD oldMode;
		GetConsoleMode(GetStdHandle(STD_INPUT_HANDLE), &oldMode);
		SetConsoleMode(GetStdHandle(STD_INPUT_HANDLE), ENABLE_LINE_INPUT);

		FlushConsoleInputBuffer(GetStdHandle(STD_INPUT_HANDLE));

		char buffer[1];
		DWORD read;
		ReadConsoleA(GetStdHandle(STD_INPUT_HANDLE), buffer, sizeof(buffer), &read, NULL);

		SetConsoleMode(GetStdHandle(STD_INPUT_HANDLE), oldMode);
		CloseHandle(GetStdHandle(STD_INPUT_HANDLE));
	}

thanks you for all my friend.. thank you both