[RESOLVED] void pointer argument in a function

[StephaneLeFou]

Hi all,

Why does the following code compile and execute without any error? I mean, the function compareid should get 2 arguments so why does the compiler not complaining, is it because of the type of arguments?
Thanks.

#include <stdio.h>
int compareid(void* info, int value);  // ansi declaration

int compareid(void* info, int value)
   /* Some code here */
   return( foundItem == value );
}

int main( void ){ 
   /* more code...*/

   compareid;
   printf("\nThis program works\n");

   return(0);
}

[GCDEF]

Doesn't compile for me.

1>c:\cg\cg\cg.cpp(7): error C2143: syntax error : missing ';' before 'return'
1>c:\cg\cg\cg.cpp(8): error C2059: syntax error : '}'
1>c:\cg\cg\cg.cpp(8): error C2143: syntax error : missing ';' before '}'
1>c:\cg\cg\cg.cpp(10): error C2143: syntax error : missing ';' before '{'
1>c:\cg\cg\cg.cpp(10): error C2447: '{' : missing function header (old-style formal list?)
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

[VictorN]

Hi all,

Why does the following code compile and execute without any error? I mean, the function compareid should get 2 arguments so why does the compiler not complaining, is it because of the type of arguments?

Doesn't compile for me.

1>c:\cg\cg\cg.cpp(7): error C2143: syntax error : missing ';' before 'return'
1>c:\cg\cg\cg.cpp(8): error C2059: syntax error : '}'
1>c:\cg\cg\cg.cpp(8): error C2143: syntax error : missing ';' before '}'
1>c:\cg\cg\cg.cpp(10): error C2143: syntax error : missing ';' before '{'
1>c:\cg\cg\cg.cpp(10): error C2447: '{' : missing function header (old-style formal list?)
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

I had the same result as GCDEF.

Dear StephaneLeFou,
please, next time check if your pseudo/code does compile before posting it to Forum!

[2kaud]

Are you compiling as c or as c++?

Where is foundItem defined?

[2kaud]

If compiled as c as opposed to c++, the program below compiles and executes.

#include <stdio.h>
int compareid(void* info, int value);  // ansi declaration

int compareid(void* info, int value)
{
int foundItem = 1;
   /* Some code here */
   return( foundItem == value );
}

int main( void ){ 
   /* more code...*/

   compareid;
   printf("\nThis program works\n");

   return(0);
}

There is a warning 'expression evaluates to a function which is missing an argument list'.

[OReubens]

   compareid;
}

This is not a function call. it is just an identifier, which ends up doing nothing in the compiled code.