[win32] - about joystick

[Cambalinho]

i'm trying calculate the button selection... i'm mean using 1,2,3,4,5,6,7....
what isn't right with these calculation:

lngButton = (log(b.dwButtons) / log(2)) + 1;

some numbers are the same with diferent buttons.
so what i'm doing wrong with calculation?

[2kaud]

Don't understand what you are trying to do??

What values can b.dwButtons take and what corresponding vakue do you want lngButton to be?? What is the type of lngButton?

[Cambalinho]

Don't understand what you are trying to do??

What values can b.dwButtons take and what corresponding vakue do you want lngButton to be?? What is the type of lngButton?

i know the 2^x=buttonvalue, but i want to know the x. i forget some math... but i'm read more.
the lngButton is long

[Cambalinho]

more easy than i thot:

long lngButton=0;

                        if (b.dwButtons!=0)
                        {
                            lngButton = log2(b.dwButtons);
                        }

and now works.
how can i test how many joysticks are connect to pc?
how i know that was joystick 1 be used?

[2kaud]

What you want to know is the bit position that is set - yes?

Have a look at _BitScanForward()
http://msdn.microsoft.com/en-us/libr...vs.120%29.aspx

[Cambalinho]

What you want to know is the bit position that is set - yes?

Have a look at _BitScanForward()
http://msdn.microsoft.com/en-us/libr...vs.120%29.aspx

please see my last post

[Cambalinho]

sorry... you have right... the JOYINFOEX.dwButtons it's a bit buttons
let me ask: how can i combine the buttons?

if(b.dwButtons==JOY_BUTTON1 &  JOY_BUTTON2)
                            MessageBox(NULL,"hi", "hello",MB_OK);

isn't the same of button 1 and 2 beeing pressed in same time?

[2kaud]

try this

if (((b.dwButtons & JOY_BUTTON1) == JOY_BUTTON1) && ((b.dwButtons & JOY_BUTTON2) == JOY_BUTTON2)) {

[Cambalinho]

try this

if (((b.dwButtons & JOY_BUTTON1) == JOY_BUTTON1) && ((b.dwButtons & JOY_BUTTON2) == JOY_BUTTON2)) {

works fine thanks.... i'm sorry, but that line can be simplificated?

[2kaud]

Depending...

It might simplify to

if ((b.dwButtons & JOY_BUTTON1) && (b.dwButtons & JOY_BUTTON2)) {

or even

if (b.dwButtons & (JOY_BUTTON1 | JOY_BUTTON2)) {

[Cambalinho]

Depending...

It might simplify to

if ((b.dwButtons & JOY_BUTTON1) && (b.dwButtons & JOY_BUTTON2)) {

or even

if (b.dwButtons & (JOY_BUTTON1 | JOY_BUTTON2)) {

Thanks for all

[Cambalinho]

sorry, but can i do something like these:
if(buttons==(JOY_BUTTON1 | JOY_BUTTON2))
//do something
???
i mean convert the b.dwButtons to buttons

[Cambalinho]

i did these:

JOYINFOEX  b;
                        b.dwSize=sizeof(JOYINFOEX );
                        b.dwFlags=JOY_RETURNALL;

                        joyGetPosEx(JOYSTICKID1,&b);
                        long h =(b.dwButtons & b.dwButtons);

                        if (h==(JOY_BUTTON1 | JOY_BUTTON2))

                            MessageBox(NULL,"hi beaury", "hello",MB_OK);

works... but tell me what you think about the conversion?
i have 1 personal reason for do these, but tell me something please

[2kaud]

long h =(b.dwButtons & b.dwButtons);

this is just

long h = b.dwButtons;

if (h==(JOY_BUTTON1 | JOY_BUTTON2))

yes providing no other bits in h are set. If other bits in h are set then the compare will fail. That is why I used bitwise and. If the only bits in b.dwButtons that can be set at the same time are JOY_BUTTON1 JOY_BUTTON2 then

if (b.dwButtons == (JOY_BUTTON1 | JOY_BUTTON2))

should be OK but IMO I would not recommend doing it like this. If in the future there was a change in the spec and bits other than JOY_BUTTON1 JOY_BUTTON2 could be set at the same time then this code would fail.

[Cambalinho]

long h =(b.dwButtons & b.dwButtons);

this is just

long h = b.dwButtons;

if (h==(JOY_BUTTON1 | JOY_BUTTON2))

yes providing no other bits in h are set. If other bits in h are set then the compare will fail. That is why I used bitwise and. If the only bits in b.dwButtons that can be set at the same time are JOY_BUTTON1 JOY_BUTTON2 then

if (b.dwButtons == (JOY_BUTTON1 | JOY_BUTTON2))

should be OK but IMO I would not recommend doing it like this. If in the future there was a change in the spec and bits other than JOY_BUTTON1 JOY_BUTTON2 could be set at the same time then this code would fail.

see what i'm doing with joystick:

else if(wParam==JoystickTimer)
                    {
                        JOYINFOEX  b;
                        b.dwSize=sizeof(JOYINFOEX );
                        b.dwFlags=JOY_RETURNALL;
                        
                        //cicle all possible joysticks
                        for (int i=0, i<16; i++)
                        {
                            int direction=0;
                            if(joyGetPosEx(i,&b)!= JOYERR_NOERROR) //if theres any error then continue to next joystick
                                continue;
                            
                            long h =b.dwButtons;
                            
                            //testing the directions
                            //will be 8 directions(inclued diagonals)
                            if (b.dwXpos == 0 && b.dwYpos == 0)
                            {
                                direction=1
                            }
                            else if (b.dwXpos == 0 && b.dwYpos == 65535)
                            {
                                direction=2;
                            }
                            Joystick(i, direction,h);
                        }

i'm doing something wrong with directionals... but i will do some consts\enum
thanks