Multiple user input and task execution

[david16]

so I have to reset the i and n used inside loop ? can you explain more ? thx

[2kaud]

your design will check for each input . I wanted to enter multiple input till -1 is entered it will exit loop and display the result you see?
my prog is working but not counting all perfects it only do count first 1 visible no the list can you tell me whats wrong with that loop ? thanks

See 1st line of my post #14.

[2kaud]

so I have to reset the i and n used inside loop ? can you explain more ? thx

No. You have to reset i and sum within the outer while loop but before entering the inner while loop. See AvDav's code in post #3.

[david16]

your program in post #14 is not display the number of perfect its not checking for it and when I enter -1 it close automatically without displaying the number of perfect found . Can you plz tell me if is it possible to make it on the one I wrote . I think I will understand it better if it was just loops because function is doing something else I was asked to do it with simple loop and inner loop you see .. thx again

[2kaud]

it close automatically without displaying the number of perfect found

then just put

system("pause");

at the end - like in your code.

[2kaud]

Can you plz tell me if is it possible to make it on the one I wrote .

yes - I explained how in post #18.

[2kaud]

If you don't understand what is happening in the code, then use the debugger to trace through the code and see the values of the variables as execution progresses. Knowing how to use the debugger is a vital skill that needs to be learnt - and now seems a good time.

[david16]

I did reset i and sum in outer loop and it worked thx for your help . I did trace and found the prob thx alot that was helpful

[david16]

I have a question about validation that I couldn't find an answer for it . if we were asked to validate each input as integer which means greater than 0 ( positive numbers) but the sentinel value is -1 and when user enter -1 it should display the number of perfects . Now is there any possible way to ignore -1 in validation and refuse any other negative input but use it as sentinel for the prog ?? . thx

[2kaud]

For validation of input, see my code in post #14.

Also consider

int num;

do {
    cin >> num;

    if (num == -1 || num > 0) {
        //number OK
        if (num > 0) {
            //Got positive number so process
        }
    } else
         //Bad number
    }
} while (num != -1);

[david16]

I'm going to try adding that to my prog . Thx for your help . I will have to continue the other parts