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Thread: [RESOLVED] string and char '\n'

  1. #1
    Join Date
    May 2018
    Posts
    67

    [RESOLVED] string and char '\n'

    I don't try to understand

    Code:
    tab=new char*[rig];
    for (int i=0; i<rig; i++)
       tab[i]=new char[col+1];
    for (int r=0; r<rig; r++)
    	for (int c=0; c<col+1; c++)
    		tab[r][c]='\n';
    I allocate two-dim matrix in heap memory, where every element is char type and I set every element to '\n'.
    Why when I ask e.g. length of row I get number different to zero?!
    If rig=5 and col=8 , strlen(tab[r]) gives 7

    tab[r] identifies a row of matrix so if I use strlen(tab[r]) first char is '\n' and It should return 0, what do you think?

  2. #2
    2kaud's Avatar
    2kaud is offline Super Moderator Power Poster
    Join Date
    Dec 2012
    Location
    England
    Posts
    6,464

    Re: string and char '\n'

    The termination delimiter for strlen() is \0 (null) , not \n.
    All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!

    C++17 Compiler: Microsoft VS2017 (15.8.7)

  3. #3
    Join Date
    May 2018
    Posts
    67

    Re: string and char '\n'

    Quote Originally Posted by 2kaud View Post
    The termination delimiter for strlen() is \0 (null) , not \n.
    ooppps !!! Excuse me

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