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June 23rd, 2018, 05:50 AM
#1
[RESOLVED] string and char '\n'
I don't try to understand
Code:
tab=new char*[rig];
for (int i=0; i<rig; i++)
tab[i]=new char[col+1];
for (int r=0; r<rig; r++)
for (int c=0; c<col+1; c++)
tab[r][c]='\n';
I allocate two-dim matrix in heap memory, where every element is char type and I set every element to '\n'.
Why when I ask e.g. length of row I get number different to zero?!
If rig=5 and col=8 , strlen(tab[r]) gives 7
tab[r] identifies a row of matrix so if I use strlen(tab[r]) first char is '\n' and It should return 0, what do you think?
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June 23rd, 2018, 06:34 AM
#2
Re: string and char '\n'
The termination delimiter for strlen() is \0 (null) , not \n.
All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!
C++23 Compiler: Microsoft VS2022 (17.6.5)
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June 23rd, 2018, 07:11 AM
#3
Re: string and char '\n'
Originally Posted by 2kaud
The termination delimiter for strlen() is \0 (null) , not \n.
ooppps !!! Excuse me
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