WCHAR* to CHAR*

[MrDoomMaster]

when using wstring and string, do I have to use transform?

I guess I failed to offer more specific details concerning my problem.

I'm dealing with a structure that, when returned from a function, contains a member with the data type of PWSTR. I need to convert this string in this structure to a CHAR*, so that I can output it using std::cout.

In your examples, you know the size of the WCHAR*, but in my case I don't know the size of the string that I need to convert, so it would be impossible to use std::transform without the appropriate iterators.

**EDIT**

I fixed it, thanks for the help though.

Here is what I have. These functions assume the destination buffer is large enough to contain the source after conversion. Buffer overrun errors could occur if the assumption is proven false:

//=====================================================================================
/*
|| ::DESCRIPTION::
|| This function will convert a WCHAR string to a CHAR string.
||
|| Param 1 :: Pointer to a buffer that will contain the converted string. Ensure this
||            buffer is large enough; if not, buffer overrun errors will occur.
|| Param 2 :: Constant pointer to a source WCHAR string to be converted to CHAR
*/
void wtoc(CHAR* Dest, const WCHAR* Source)
{
    int i = 0;

    while(Source[i] != '\0')
    {
        Dest[i] = (CHAR)Source[i];
        ++i;
    }
}

//=====================================================================================
/*
|| ::DESCRIPTION::
|| This function will convert a CHAR string to a WCHAR string.
||
|| Param 1 :: Pointer to a buffer that will contain the converted string. Ensure this
||            buffer is large enough; if not, buffer overrun errors will occur.
|| Param 2 :: Constant pointer to a source CHAR string to be converted to WCHAR
*/
void ctow(WCHAR* Dest, const CHAR* Source)
{
    int i = 0;

    while(Source[i] != '\0')
    {
        Dest[i] = (WCHAR)Source[i];
        ++i;
    }
}