menu of character strings

[aijazbaig1]

Hello there.
If u read the specification for the fflush function it very clearly mentions that its effect is undefined for input streams making the function a not too good choice for cleaning input streams.
I do not know if standard C has any other functions which can do that.

However I used a different method and it worked. I used to read and ignore characters until a newline character is encountered. I only check for the 1st character and make my decision on that.

If you know of any other function which is a part of the standard C library which can flush and whose effect is defined even for input streams, please do let me know.

Heres the code:

#include <stdio.h>
#include <string.h>

int main()
{
	const char *idioms[] = {"create array","free memory",
							 "find smallest","check for palindrome"};
	char choice;
	int i,flag,equal;
	//flag=0; removed this line..
	do
	{
		char string1[100] = {0};
		do
		{
			fputs("enter the string\n",stdout);
			fgets(string1,100,stdin);
		}
		while(*string1 == '\n' || *string1 == '\r');
		if (string1[strlen(string1)-1] == '\n') string1[strlen(string1)-1] = '\0';
		printf("\n\n");
		flag=0;//added this line...
		i=0;
		do
		{
			equal = (_strnicmp(idioms[i],string1,strlen(idioms[i])));
			if(equal==0)
				{
				printf("you opted for entry number %d , %s \n",i,idioms[i]);
				flag = !equal;//flag indicates that a match was found.
				};
			++i;
		}
		while(!flag && i<=3);
		if (flag == 0)  // no matching entries found
			fputs ("\nThe input string didnt match any of the entries!\n\n", stdout);
		do
		{
			fputs("do u wish to continue?\nenter a y or a Y for yes\n\n",stdout);
			choice = getchar();
		}
		while (choice == '\n' || choice == '\r');
		while (getchar() != '\n');
		fputs("\n",stdout);
	}
	while(choice == 'y' || choice == 'Y');
	return 0;
}