xsl condition

[laasunde]

Given this XML;

<Nodes>
   <Node>
     <Software id="A" version="1.2.3.4"/>  
     <Software id="B" version="2.2.3.4"/>
     <Software id="C" version="3.2.3.4"/>

Trying to get version for Software with ID='a', doing this fails;

<xsl:for-each select="/Nodes/Node">
  <xsl:value-of select="./Software[@id='A']/@version"/>
</xsl:for-each>

The two below work fine but are not specific enough (can fail if order is different)

<xsl:for-each select="/Nodes/Node">
  <xsl:value-of select="./Software/@version"/>
</xsl:for-each>

//and 

<xsl:for-each select="/Nodes/Node">
  <xsl:value-of select="./Software[1]/@version"/>
</xsl:for-each>

Appreciate any input (apologise for any typo's - typed the example in by memory).

[bharadwajrv]

this may not be the best solution.. but this will work....

Cheers
Venu

 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
	<xsl:template match="Nodes">
		<NodeDetails xmlns="http://tempuri.org">
			<xsl:for-each select="/Nodes/Node/Software">
				<xsl:if test="@id='B'">
						<ver> <xsl:value-of select="@version"/>	</ver>
					</xsl:if>
				</xsl:for-each>
		</NodeDetails>
	</xsl:template>
</xsl:stylesheet>

[laasunde]

Thanks for the reply.

This didn't work, nothing appears inbetween <ver>.

<xsl:for-each select="/Software">
  <xsl:if test="@id='B'">
    <ver> <xsl:value-of select="@version"/></ver>
  </xsl:if>
</xsl:for-each>

However this works but obviously prints both versions. Is there anything special regarding the equals operation?

<xsl:for-each select="/Software">
  <xsl:if test="@id">
    <ver> <xsl:value-of select="@version"/></ver>
  </xsl:if>
</xsl:for-each>

Using Winxp sp2, .NET 1.1 and IIS 5.1

[bharadwajrv]

surprisingly it is working on my machine ! .. i'm not sure why it is not working on your PC...

Here by i'm sending both XML and XSL file i used...

let me know error in this...

Cheer
Venu