Little question about char convertion

[AlanGRutter]

Are you saying you replaced

char st[];

by

char *st;

You haven't allocated any memory for the variable - you need to do this in both cases. I think you are lucky in the first case.

Try

char st[25] = {0}; // allow plenty of room

or

char *st = new char[25];

or better yet use an STL string.

Regards
Alan