placing int into char*

[ductiletoaster]

ok so i want to be able to take an integer break it up and place it into an char*
example: int x = 10
take 10 make it into '1' and '0' and then place those into char*

now i have a method that does this and it looks like this..........buf is a char*

      std::ostringstream sout;
      sout << x;
      std::string s(sout.str());
      length = s.length(); // Sets length equal to the length of the string
      buf = new char[length];
      const char *sz = s.c_str(); // Sets const char * equal to the string
      buf = (char*) sz; // Casts sz to char* from const char * and sets buf equal

The problem is that iw ould rather now use the string class because unfortunatly im doin an assignment that is basically the string class. So any suggestions through them at me. Thank you

[ductiletoaster]

Ok so let me clarify..............

sudo code:

int x = 10;
char* buf = new char[ number of digits ];
take x place into buf like '1' and '0'

 so that...

buf[0] = 1
buf[1] = 0

[Etherous]

I just typed this up on the fly, so there's probably some errors:

int intPow(const int n, const int p) // Gets n to the power of p
{
  int ret = n;
  for(int i = 1; i < p; i++)
    ret *= n;
  return ret;
}
int intLog10(const int n) // Gets log base 10
{
  int ret = 0, num = n;
  while(num > 10)
  {
    num /= 10;
    ret++;
  }
  return ret;
}
char* intToStr (const int n) // Call this one with the number and it (maybe) will return it in string form
{
  int strLen = intLog10 + 2, num = n, temp, temp2;
  char* ret = new char[strLen];
  for(int i = 0; i < strLen-1; i++)
  {
    char[i] = (temp2 = (num &#37; (temp = intPow(10,strLen-i-2)))) + '0';
    num -= temp * temp2;
  }
  ret[strLen-1] = '\0';
  return ret;
}

There's also itoa, of course:
http://www.cplusplus.com/reference/c.../cstdlib/itoa/

[ductiletoaster]

very nice i will try it and get back her when i figure out what happens

[Lindley]

Something worth considering if you use itoa or a similar function is the the number with the most digits that could *possibly* be held in an int is -2147483648. So if you pass a fixed-sized char array with at least 12 bytes to itoa, you know you'll have enough space.

[ductiletoaster]

just out of curiosity what is the #include for iota...... and isnt it a C# function
correct me if im wrong

[laserlight]

Something worth considering if you use itoa or a similar function is the the number with the most digits that could *possibly* be held in an int is -2147483648.

Though strictly speaking an int could have an even larger range on a given implementation, but such a consideration is not so important for a school assignment.

just out of curiosity what is the #include for iota...... and isnt it a C# function
correct me if im wrong

It is not part of the C++ standard library, but if it is available you can probably #include <cstdlib> to use it.