Open File Dialog

[marsh]

Hello i am making a simple program in visual c++, i have it so that when i hit a button the Open File dialog pops up. But when i open something i want it to return the file name of what i opened so that my program my deal with it.

Here is my attempt

string account2;
account2 = openFileDialog1->FileName;

The error i receive.

binary '=' : no operator found which takes a right-hand operand of type 'System::String ^' (or there is no acceptable conversion)


Can someone please step me in the right direction? Many Thanks - marsh

[shirani]

This works quite fine, try it

String^ account2;
account2=openFileDialog1->FileName;

THANX

[olivthill2]

It seems your example is for Visual basic of C++.

Visual C++
private:
void button1_Click( Object^ /*sender*/, System::EventArgs^ /*e*/ )
{
Stream^ myStream;
OpenFileDialog^ openFileDialog1 = gcnew OpenFileDialog;

openFileDialog1->InitialDirectory = "c:\\";
openFileDialog1->Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
openFileDialog1->FilterIndex = 2;
openFileDialog1->RestoreDirectory = true;

if ( openFileDialog1->ShowDialog() == System::Windows::Forms:ialogResult::OK )
{
if ( (myStream = openFileDialog1->OpenFile()) != nullptr )
{
// Insert code to read the stream here.
myStream->Close();
}
}
}

(Source: http://msdn.microsoft.com/en-us/libr...iledialog.aspx)

[marsh]

Thank you i got it working.

[ovidiucucu]

[ moved thread ]