output produced by function call

[jimJohnson123]

For the following function can one of you guys take a look and see if what I have at the bottom is correct..

void f(char ch)
{
if (('A' <= ch) && (ch <= 'H'))
{
f(ch - 1);
cout << ch;
}
else
cout << endl;
}

Determine the output that will be produced by the following function calls
f('C')
I think it is B

f('G')
I think it is F

[Lindley]

I'm assuming you meant for that to test >= 'A', rather than <=, because otherwise you're just going to get a bunch of gibberish no matter what.

[jimJohnson123]

no I double checked and the statement reads if (('A' <= ch) && (ch <= 'H'))

[leoalvesmachado]

Why don't you implement it to see the result by yourself? It's a very small code, and you have already typed most of it...

[laserlight]

Trace the recursion and you will see that both your answers are wrong. But as leoalvesmachado suggests, you might want to compile and run a program with this to confirm it.

Of course, one assumption here is that the character set has the letters from 'A' to 'Z' in contiguous alphabetical order, as in ASCII.

[Lindley]

no I double checked and the statement reads if (('A' <= ch) && (ch <= 'H'))

Well then, the problem is trivial, because that condition is going to be false for either of those inputs.

[jimJohnson123]

I think I figured it out...ABC for answer one and ABCDEFG for answer two?

[laserlight]

Well then, the problem is trivial, because that condition is going to be false for either of those inputs.

I may be missing something, but the condition should evaluate to true for both.

I think I figured it out...ABC for answer one and ABCDEFG for answer two?

Yes, although a newline is also printed before those outputs.

[Lindley]

I may be missing something, but the condition should evaluate to true for both.

Okay, you're right. And I've been talking nonsense in this thread. I didn't realize the constant was on a different side in each expression----I just saw the same operator used twice and my brain went "Huzzwhaaa???".