Convert int of unknown number of bits to 32 bits int

[andrey_zh]

2196550012_10 = 82ECB17C_16

82_16 = 130
EC_16 = 236
B1_16 = 177
7C_16 = 124

Seems you have to use masks if you need to split an integer to four octets.

a.b.c.d

a = (ip >> 24) & 0xFF;
b = (ip >> 16) & 0xFF;
c = (ip >>  8) & 0xFF;
d = (ip      ) & 0xFF;

And yes some IP-s will be stored as negative integers.

Tip: read as long, then convert to int:

long a = 2196550012L;
System.out.println( (int)a );

Gives the result: -2098417284_10 = 82ECB17C_16.