Printing patterns

[Lindley]

printf("%c         %c\n", '*', '*');

While this will work, substituting literals is really not necessary here:

printf("*         *\n");

will do the same thing.

The instructor referred to it as a C++ class anyway.

Well, to be blunt, there are a lot of instructors who claim to be teaching C++, who are actually teaching "C with a few bits of C++ syntax thrown in". That isn't the way professional programmers write C++, but it is unfortunately very common in schools. The reason for this is that C makes it easier to teach the underlying data structures and algorithms than proper C++, because proper C++ does a lot of the low-level stuff for you. It's important to learn those low-level ideas, but you should also become familiar with the "right" way of doing things, because it's both easier and safer.

[adam86107]

OK, so here is what I've tried to do and apparently I am way off base. Everything I've tried keeps getting implicit declarations of the functions in main, but without modifying main I cant seem to figure out how to get rid of this. Here is my latest failure:

int main (void) {
print_1_9();
print_2_7();
print_3_5();
print_4_3();
print_5_1();
print_6_0();
print_5_1();
print_4_3();
print_3_5();
print_2_7();
print_1_9();
return 0;
}
int myfunction (void) {
print_1_9;
printf("* *\n");
print_2_7();
printf("** **\n");
print_3_5;
printf("*** ***\n");
print_4_3;
printf("**** ****\n");
print_5_1;
printf("***** *****\n");
print_6_0;
printf("************\n");
return 0;
}

Any extra help is much appreciated as this program is due today.

[adam86107]

I've changed it up some but still to no avail. Here's the newest:

int main (void) {
print_1_9();
print_2_7();
print_3_5();
print_4_3();
print_5_1();
print_6_0();
print_5_1();
print_4_3();
print_3_5();
print_2_7();
print_1_9();
return 0;
}
int myfunction (void) {
int print_1_9();
printf("* *\n");
return 0;
}
int myfunction1 (void) {
int print_2_7();
printf("** **\n");
return 0;
}
int myfunction2 (void) {
int print_3_5();
printf("*** ***\n");
return 0;
}
int myfunction3 (void) {
int print_4_3();
printf("**** ****\n");
return 0;
}
int myfunction4 (void) {
int print_5_1();
printf("***** *****\n");
return 0;
}
int myfunction5 (void) {
int print_6_0();
printf("************\n");
return 0;
}

[ttrz]

Name your functions print_1_9, print_2_7, print_3_5, print_4_3, etc. Don't name them myFunction - that is just something I used when giving you an example.

To keep it simple, implement the functions first, before main. See if this helps you.

#include <iostream>

void print_1_9() {
printf("*         *\n");
}

int main (void) {
print_1_9();
return 0;
}

If you can't figure out how to make it work from this example, I think you are in trouble and should read the first few chapters of your C or C++ programming book again.