[RESOLVED] Segmentation fault and also bad initalization

[Paul McKenzie]

Ok, so I set the value of s just to see what happens. Still getting the segmentation fault.

That is because "s" is a string-literal, and you cannot write to string literals.

Here is a much simpler program:

int main()
{
   char *s = "abc123";
   s[0] = 'x';
}

This program also crashes, and for the same reason your program crashes. The s is a string-literal, and I'm attempting to change the first character from 'a' to 'x'. Crash.

Only writeable char arrays, and memory allocated from the heap can be modified.

int main()
{
   char s[] = "abc123";
   s[0] = 'x';
}

This code now doesn't crash, since s is a writeable array of char.

Regards,

Paul McKenzie