Reverse byte order using union, How?

[jbp2004]

Ok, I got the answer I want. Now, I want to share the code here

void GetReverseByteOrder(int n) {
   union {
      int nGiven;
      unsigned char val[4];
   } HEXA;

   HEXA.nGiven = n; /* n is input of user */
   for (int i=0; i<4; i++)
      printf("%02x",HEXA.val[i]);
}

What does this piece of code do?
-- user types in a number, say 123456
-- 123456 is stored to n and passed to HEXA.nGiven
-- we know that 123456 is 1E240 in base 16
-- now, we wanted to reverse 1E240 making it 40E20100
-- 40E20100 is generated by the code above

How come? Can u imagine how? :-)

That's it! A generous man from codeguru shared the above code. I just did a little modification. I forgot his username here in this forum but anyway, many many thanks to him!