new operator

[potluck]

Hey im just a begginer at this language and im having a real difficult time. Im not sure what this means. I was asked to create like six forms which i did but now it says do this. im kinda lost please help.

You MUST create all the forms using the new operator. For example,


int main()
{
form *[5];
return 0;
}

[jfaust]

form[0] = new form();
form[1] = new form();
...
form[5] = new form();


or (better) ...

for( int i = 0; i < 5; ++i )
{
form[i] = new form();
}

Jeff

[Gabriel Fleseriu]

Originally posted by jfaust
form[0] = new form();
form[1] = new form();
...
form[5] = new form();


or (better) ...

for( int i = 0; i < 5; ++i )
{
form[i] = new form();
}

Jeff

That probably was a typo, but if form is a type name

form[i] = new form();

won't compile. I think you meant

const int forms = 5
form *form_[forms];
for( int i = 0; i < forms; ++i )
{
   form_[i] = new form();
}

[jfaust]

Right. I was attempting to keep the same "form" as the OP (pun intended). Thanks for catching that and avoiding further confusion.

Jeff

[potluck]

im still in the dark.
I have a base class form and have to create osap, school, bank and apply forms. Could someone explain how i would use the new operator please.

[cup]

I assume osap, school, bank and apply forms are derived from form, so you'd possibly have something like

class form
{
public:
    virtual ~form() {}
};
class osap: public form {}
class school: public form {}
class bank: public form {}
class apply: public form {}

main ()
{
    // To create pointers to the different forms
    form* aform[4];
    int i = -1;
   
    aform[++i] = new osap;
    aform[++i] = new school;
    aform[++i] = new bank;
    aform[++i] = new apply;
    ...


    // When you want to delete them
    for (i = 0; i < 4; i++)
        delete aform[i];
}

The declaration creates pointers. Each pointer has to be assigned an instance using the new operator.

[potluck]

one question , what does the virtual ~form do??

[jfaust]

When you call delete on the base class object, it will call the correct derived class destructor. Any class acting as a base class should always have a virtual destructor.

Jeff

[cup]

It is the destructor. When aform[i] is deleted, it calls the destructor of the derived object: not just the form destructor. The easiest way to see this is to put couts in the destructors.