printing char array

[ct_eubanks]

I am trying to print a char array with an * between each character. I am getting my input from the user and since I can not determine the length of the string I am unsre how to output the string with the correct number of astricks.

any help is greatly appreciated

[Runt888]

strlen will give you the number of characters. Try this:

for( int x = 0; x < strlen( myArray ); x++ )
    cout << myArray[x] << "*";
cout << endl;

Kelly

[ct_eubanks]

Hot dog.. That was it. I guess that is what I was supposed to learn out of that exercise. How to use strlen.

I have created 2 other little programs to play with strlen and it is pretty cool.

Thanks alot bud.

[PaulWendt]

It looks like you're not at this point yet, but you could also use
the STL:

#include <algorithm>
#include <iostream>
#include <iterator>
using namespace std;

int main(int argc, char* argv[])
{
   char theArray[] = "This is the array";

   copy(&theArray[0], &theArray[strlen(theArray)], ostream_iterator<char>(cout, "*"));
   cout << endl;

   return 0;
}

Whether the above is easier to understand than the loop
approach is debatable

--Paul

[ct_eubanks]

Looks a little confusing right now but thanks for the reply..