Pointers

[mkan]

I have a silly doubt

1) int *ptr
int count=6;
ptr &count;

cout<<*ptr<<endl;

2) int *ptr=5

cout<<*ptr<<endl;

In both the cases the value of *ptr is 5. Then why do we always do it as in the first case

[Timir Panchal]

In the first case u r makeing Ptr to point count.

[Latem]

that code shouln't even compile, and the problem is with #2 and not with #1.

try this:

#include <iostream>

using namespace std;

void foo1();
void foo2();

int main()
{
	foo1();
	foo2();
	return 0;
}
 
void foo1()
{
	int *ptr;
	int count=6;
 	ptr = &count;
	
	cout << *ptr << endl;
}

void foo2()
{
	int *ptr;
	
	*ptr = 5;
		
	cout << *ptr << endl;
}

that output's

6
5

I dont know if you just forgot the "=" in your #1, but as you can see that works perfectly.
In your #2, the line:

int *ptr=5

Assuming you just forgot ";", should generate a compiler error (using g++):

ptest.cpp: In function `void foo2()':
ptest.cpp:26: error: invalid conversion from `int' to `int*'

Latem

[Paul McKenzie]

void foo2()
{
  int *ptr;
  *ptr = 5;
//...
}

The behavior is undefined. The program may crash on the line *ptr =5 since ptr is uninitialized.

Regards,

Paul McKenzie

[mkan]

hi,

Yes i have forgotten "="
anyway my doubt is , is it must than i have to say

ptr= &count

becuase when i say int *ptr=5
and cout<<*ptr;

output is 5 and there is no problem , then why are we giveing the line
ptr= &count

[Latem]

becuase when i say int *ptr=5
and cout<<*ptr;

output is 5 and there is no problem ,

how can this work? it doesn't even compile for me. You are trying to assign an int to *int.

You can do:

int* ptr;
int count=6;
ptr = &count;
 
cout << *ptr << endl;

Here a pointer to integer (ptr) is declared. integer count is assigned a value of 6. Then ptr is made to point to the address of count.

or

int* ptr = new int; 	// dont know how I forgot that earlier
*ptr = 5;
cout << *ptr << endl;
delete ptr;

here you allocate an integer, and then sets the value of allocated space to 6.

or

int* ptr = new int(5);
cout << *ptr << endl;
delete ptr;

here you allocate an integer abd initialize it to 6.

I am not sure if I am using the right "temenology" and words. but that's as simple as I can exmplain it.

Latem