double is shown as float in size (newbie)

[dankilman]

Hello there codeguru gurus...
here is my code:

#include <iostream>
using namespace std;

double sqrtOfTwo(int counter)
{
    if (counter==0)
        return 0;
    else 
    {
        counter--;
        return 1.0/(2.0+sqrtOfTwo(counter));
    }    
}

int main()
{
    cout << rec(10); // doesn't really matter what number comes here
    return 0;
} 

when i run this code the output will be : 0.414214 , which is shorter than what i'd expect to receive, having declared this function as a double, not as a float. this may be something i simply do not understand in the way variable types work. either way, i'd really appreciate details regarding this issue.

[ZuK]

This is just because of the default ostream outputprecision.
try like this

#include <iostream>
#include <iomanip>
using namespace std;


double sqrtOfTwo(int counter) {
    if (counter==0)
        return 0;
    else  {
        counter--;
        return 1.0/(2.0+sqrtOfTwo(counter));
    }
}

int main() {
    cout << setprecision(12) << sqrtOfTwo(10); // doesn't really matter what number comes here
    return 0;
}

Kurt

[dankilman]

thanks!
that was quick...