Read specified number of char from istream

Hi,

What is the most efficient way to read specified number (n) of characters from an istream to a std::string?

Thanks.

Set the field width for input, read the string, set the string to the just-read-in input.

Chris.

#include <iostream>
#include <iomanip>
#include <string>
using namespace std;

void read_it(void)
{
char buffer[81];
cin >> setw(sizeof(buffer) / sizeof(char)) >> buffer;
string the_string = buffer;
}

int main(int argc, char* argv[])
{
read_it();

return 1;
}

:)

to read the char from the istream,
you can use like the following:

Code:

---

istream in;
streambuf* p = in.rdbuf()
std:string += p->sgetc()

---

or you can use p->sbumpc() to get the char too.
the difference between sgetc() and sbumpc() is that:
sgetc() return the current read char but donot move to next position, while sbumpc() will move to next position.

I don't know much about stl, so please double-check.

Code:

---

void read( string& dst, int count, istream& is )
{
  dst.resize(count, 0);
  is.read( dst.begin(), count );
}

// usage
string s;
read(s, 10, cin);

---

Regards,

This is what I need. Thanks.