Seperating Integer & Fractional Part

Helo,

I have a double value ,say 1.4.
double val = 1.4;
I want to seperate the Integer & Fractional Part. "1" & "4" from that val like
int val1 =1
int val2 = 4(without the ".")

How Can I do that.
Thanks...

Code:

---

void main()
{
        float a=5.8;
        int i,j;
        i=a;
        j= (a -i) *10;

        printf("%d  %d", i,j);
}

---

but it will work only if your fractional part length is 1.
Otherwise you won't get the extract fractional portion by this code

Try:

Code:

---

double d, ip;
d = 1.4
int fp = 10 * modf( d, &ip );

---

Regards,

I tried the 2nd choice,bit its not working for 1.2 & 1.4

Quote:

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Originally posted by Kohinoor24
I tried the 2nd choice,bit its not working for 1.2 & 1.4

---

It is not clear what “not working” means. I did not check the code, but it should work. If you have rounding problems you may add/subtract 0.5:

Code:

---

  int i = int(10. * 0.39); // i == 3
  int j = int(10. * 0.39 + 0.5); // j == 4

---

Regards,

#include "stdio.h"
void main()
{
double i= 23.55;
char temp[10], temp1[10];
int val1, val2;
sprintf(temp,"%.2f",i);
for (int j=0;((temp1[j]=temp[j])!='\0')&&(temp[j]!='.');j++);
if (temp1[j]=='\0')
{
sscanf(temp1,"%d",&val1);
val2=0;
}
else
{
temp1[j]='\0';
sscanf(temp1,"%d",&val1);
j++;
for (int k=0;((temp1[k]=temp[j])!='\0');j++,k++);
sscanf(temp1,"%d",&val2);
}
/* val1 contains integer & val2 contains fraction*/
}

regards,
sursura

Maybe this would be a bit easier... ;)


// Value to be "split"
float value (1.999);

// Set the decimal precision
int precision(2);

int integer= (int) value;
int fraction = (int) ((value - integer)*pow(10, precision));

// integer = 1 and fraction = 99

Villemos.

Thanks...