an auto_ptr question

I declared:
auto_ptr<char> a(new char[20]);

My question is how I can initialize a with a string?

Hi,
U need to call explicitaly strcpy to copy a string.
u can not initialize it directly.

Vinod

Quote:

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Originally posted by vinodp
Hi,
U need to call explicitaly strcpy to copy a string.
u can not initialize it directly.

Vinod

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I am sorry I don't understand what you said. Actually, strcpy doesn't take the auto_ptr<char> as a parameter type. So how could you use strcpy to copy a string to a in question?

strcpy(a.get(), "Codeguru");
Beware of length of the string & allocated char length.
My suggestion is instead of this use STL::string class.

Vinod

Code:

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auto_ptr<char> a(new char[20]);

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auto_ptr can not be used for arrays. It calls delete,
not delete [] on the object it owns.

Use one of the standard containers (std::string as
already suggested or something like :

vector<char> a(20);

then if you need to pass to a function that expects a c-style
string, you use : &a[0]

Quote:

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Originally posted by vinodp
strcpy(a.get(), "Codeguru");
Beware of length of the string & allocated char length.
My suggestion is instead of this use STL::string class.

Vinod

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I don't think strcpy(a.get(), "Codeguru") is going to work.

Quote:

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Originally posted by Philip Nicoletti

Code:

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auto_ptr<char> a(new char[20]);

---

auto_ptr can not be used for arrays. It calls delete,
not delete [] on the object it owns.

Use one of the standard containers (std::string as
already suggested or something like :

vector<char> a(20);

then if you need to pass to a function that expects a c-style
string, you use : &a[0]

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I guess you are right. One way is like this:
auto_ptr<string> a(new string("Hello\n");