different object when used in other class/object

I declared
static SOCKET socket;
static SOCKET client ;
in dialog.h

socket.create()
socket.listen()

OnAccept()
{
Accept(client,0,0);
client.Send(data,strlen(data));//it works fine here
}

BUT in dialog.cpp(main)
I start another thread for serial comms...
in that thread, I tried

client.Send(data,strlen(data));

IT doesnt work....
so I did a check b4 I send.....

Client.GetPeerName(ClientIP,portnumber);
// ClientIP=""
//portnumber=3435973836

above r the numbers I got
the obj is not the one that I have in OnAccept.....
any idea wat happened?

:confused:

i tried declaring the client socket as extern in the .h

but once I tried to

OnAccept()
{
server.Accept(Client,0,0)
//It immdeiately fail a debug assertion
//error= INVALID_SOCKET
}

anyone?

:confused:

:confused:

The code you posted is rather unclear, it won't even compile. What are you trying to do with the followin statements?

Code:

---

static SOCKET socket;

socket.create()
socket.listen()

---

Note that SOCKET is a handle (it is typedef'd as unsigned int), not a class. So socket.create() can't possibly compile.

sorry abt that....

its just to illustrate that its of socket type onli......
it psuedo code......
actually code is here..

http://www.codeguru.com/forum/attach...&postid=822809

:confused:

Your zip archive is damaged... :rolleyes:

The static keyword when applied to an object at file scope means that each translation unit that includes your header will have its own copy of the object to work with. Either make the object a normal global object in your cpp with an extern declaration in the header or singletonise...

I tried declaring the client socket object in .cpp
and extern in .h

it can compile and link

but when I accept the connection,
the client fail the debug assertion...
error is the client is a INVALID_SOCKET.

anyone?
i'll try to post the code again later.....

:confused:

Quote:

---

Originally posted by hamham
:confused:

---

:confused: :confused:

its just a dummy expression to up the thread.....

anyway, here's the code...





Hi...

I am very sorry about it....
I really dont know that an email will be sent to those who have posted to my thread......
:(

I am using thos post and not a new post so that it wont generate another email to u guys.....

but i downloaded the code and open...
it seems to b alright.....

Quote:

---

Originally posted by hamham
its just a dummy expression to up the thread.....

---

May I ask you to drop that habit? Each time you add a dummy post, everybody who has posted to your thread will get an e-mail notification. The reason why you don't get any replies is not that your thread is not seen, but that the information you provide regarding your problem is incomplete or incorrect.

BTW: The second zip file you posted is damaged too.