int and float pointer variables

Hello guys, i need some help, how many bytes an int, float pointer variable in ram, a am using win2000,xp on intel machine.

i make program that display

code:
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int i=4;
int *p;
p=&i;
clrscr();
cout<<p<<endl; //0x8f1fff4
p++;
cout<<p<<endl; //0x8f1fff6
float p1=1.1;
float *p2;
p2=&p1;
cout<<p2<<endl; //0x8f1fff0
p2++;
cout<<p2; //0x8f1fff4

--------------------------------------------------------------------------------


how many bytes these int and float pointers take in ram, according to this it is showing
int * takes 2 bytes
float * takes 4 bytes.

thanks for clearing my concept.

This is correct.

integer pointer takes 2 bytes and
float pointer takes 4 bytes.

THANKS JOSCOLLIN

Quote:

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This is correct.

integer pointer takes 2 bytes and
float pointer takes 4 bytes.

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That's weird with the following code

Code:

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float *TestFloat;
int *TestInt;

unsigned int SizeFloat=sizeof(TestFloat);
unsigned int SizeInt=sizeof(TestInt);

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SizeFloat=4 and SizeInt=4 when checked in the debugger.

TDM

Quote:

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Originally posted by joscollin
This is correct.

integer pointer takes 2 bytes and
float pointer takes 4 bytes.

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This is not correct...the size of a pointer is the same and equals 4 bytes on a 32-bit processor...

Depends on the h/w and os we use.
Anyway this is true in ANSI C.

Quote:

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Depends on the h/w and os we use.
Anyway this is true in ANSI C.

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Are you saying that by ANSI C it is correct that float * and int * can take different sizes?

IMO then using void pointers will make little sense.

Regards

Quote:

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Originally posted by nsh123
Are you saying that by ANSI C it is correct that float * and int * can take different sizes?

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No...ANSI C does not have to do much with it...the size of variables are based on the architecture in the first place...

pointers are the same size irregardless of type.

char *a;
int *b;
unsigned long *c;
double *d;


no matter what you put, the size is always going to be 4 on a 32 bit system. remember, your pointer is just something that "points" to a spot in memory. if it was only 2 bytes you could only point to memory in the first 64kb and well that obviously doesn't cut it anymore.