hex char to int in C

I'm trying to feed a single char (as an int) to this function an then get back the hex value but I"m getting complier errors...

Code:

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254>int hex_to_int(int c)
255>{
256>
257>  if((c - (int)'0' >= 0 )&&(c - (int)'0' < 10))
258>  {
259>          return (c - (int)'0');
260>  }
261>
262>  char hexalpha[] = "aAbBcCdDeEfF";
263> int i;
264> int answer = 0;
265>
266>  for(i = 0; answer == 0 && hexalpha[i] != '\0'; i++)
267>  {
268>    if(hexalpha[i] == c)
269>    {
270>      answer = 10 + (i / 2);
271>    }
272>  }
273>
274>  return answer;
275>}

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gives me:
C:\uiox_dev\UIOX Sources\Rcl.c(262) : error C2143: syntax error : missing ';' before 'type'
C:\uiox_dev\UIOX Sources\Rcl.c(263) : error C2143: syntax error : missing ';' before 'type'
C:\uiox_dev\UIOX Sources\Rcl.c(264) : error C2143: syntax error : missing ';' before 'type'
C:\uiox_dev\UIOX Sources\Rcl.c(266) : error C2065: 'i' : undeclared identifier
C:\uiox_dev\UIOX Sources\Rcl.c(266) : error C2065: 'answer' : undeclared identifier
C:\uiox_dev\UIOX Sources\Rcl.c(266) : error C2065: 'hexalpha' : undeclared identifier
C:\uiox_dev\UIOX Sources\Rcl.c(266) : error C2109: subscript requires array or pointer type
C:\uiox_dev\UIOX Sources\Rcl.c(268) : error C2109: subscript requires array or pointer type

any ideas where these are coming from?

thanks

In 'C' variable declarations must be at the beginning of a scope block. C++ allows them to be moved to the point of nearest use, but not 'C'...

Quote:

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Originally posted by TheCPUWizard
In 'C' variable declarations must be at the beginning of a scope block. C++ allows them to be moved to the point of nearest use, but not 'C'...

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I think C99 standard allows that. But of course, since most C compiler is not C99 compliant yet, declaration must be placed right at the beginning of the scope block.

You can also try this by changing you file extension to .cpp from .c. As 'TheCPUWizard' mentioned, you can define the scope of those variables, by using the '{' and '}' braces.