2 adapters,one can broadcast and the other can not.
PC A have 2 adapters,One adapter's IP is "192.168.0.95";another is "192.168.0.188".Everything is well and sendto return the bytes right.but the application in PC B can received from "192.168.0.188" but not "192.168.0.95".I can ping "192.168.0.95" from PC B.I disabled 192.168.0.188 and can copy files from PC B. indicates that the network status is good.
Anyone help me? thanks a lot.
the code is:
int iReturn;
SOCKET socketResponse;
sockaddr_in stSendToAddress;
BOOL bSocket = TRUE;
bool opt = true;
int nlen = sizeof(stSendToAddress);
stSendToAddress.sin_family = AF_INET;
stSendToAddress.sin_addr.s_addr = INADDR_BROADCAST;
stSendToAddress.sin_port = htons(68);
socketResponse = socket(AF_INET,SOCK_DGRAM,IPPROTO_UDP);
iReturn = setsockopt(socketResponse,SOL_SOCKET,SO_BROADCAST,(char FAR *)&opt,sizeof(opt));
sockaddr_in stAdapterAddress;
memset(&stAdapterAddress,0,sizeof(stAdapterAddress));
stAdapterAddress.sin_family = AF_INET;
//different only in m_szDHCPIP
stAdapterAddress.sin_addr.s_addr = inet_addr(m_szDHCPIP);
stAdapterAddress.sin_port = htons(68);
if(WaitForSingleObject(theApp.m_hMutex,20000) == WAIT_OBJECT_0)
{
iReturn = bind(socketResponse,(sockaddr *)&stAdapterAddress,sizeof(sockaddr_in));
if(iReturn==SOCKET_ERROR)
{
DWORD dwError = WSAGetLastError();
TRACE("bind socket error.\r\n");
}
iReturn = sendto(socketResponse,(const char*)&stDHCPResponsePacket,BOOTP_MIN_LEN,0,(sockaddr*)&stSendToAddress,nlen);
if(iReturn==SOCKET_ERROR)
{
TRACE("send error\r\n");
// AfxMessageBox("send error\r\n");
}
else
{
// AfxMessageBox("send\r\n");
}
closesocket(socketResponse);
ReleaseMutex(theApp.m_hMutex);
}
Re: 2 adapters,one can broadcast and the other can not.
Hi,
Maybe not a C++ issue, is there a switch or router between PC B and the adaptor with 192.168.0.95? The fact that you can ping between them doesn't mean you can send a broadcast. Networks are often set up so that broadcast is only possible over the local segment.
Cheers,
Alan
Re: 2 adapters,one can broadcast and the other can not.