how to release the memory used by a structure?

I am trying to catch some memory leakage in others code. It is really a suffer.
My question is that the structure array is not given memory using new or malloc, it is given value directly, so do I need to release it?
If I need to do it, how should I do it?
Should I release the field one by one? or something else.
Thank you very much.
Can you please give some sample code about this ??

the code is below:

struct THREAD_PARMS {
// Need change
IClientVirtualDeviceSet *vds;
const char * vdName;
const char * filePath;
bool doCompression ;
int taskId;
int taskScheduleId;
int taskExecId;
JavaVM *vm;
jclass obj ;
jobject execResult;
char* lpInstanceName;
int first;
};

THREAD_PARMS parms[32]; // each thread needs its own parm block
HANDLE children[33]; // 32 is maximum number of streams.

for (ix=0; ix<numFiles; ix++)
{
//get the JVM
JavaVM *vm ;
env->GetJavaVM(&vm) ;

// All threads share the same virtual device set,
// but must operate on different virtual devices.
//
if(lpInstanceName == NULL)
{
//printf("startSecondaries: Default Instance\n");
parms[ix].vds = vds;
parms[ix].vdName = vdNames[ix];
parms[ix].filePath = filePaths[ix];
parms[ix].doCompression = doCompression ;
parms[ix].obj = obj;
parms[ix].taskId = taskId;
parms[ix].taskScheduleId = taskScheduleId;
parms[ix].taskExecId = taskExecId;
parms[ix].vm = vm;
parms[ix].execResult = execResult ;
parms[ix].lpInstanceName = lpInstanceName;
parms[ix].first = 1;

children[ix] = (HANDLE)_beginthreadex (
NULL, 0, runSecondary, (void*)&parms[ix], 0, &threadId);
}

No, you don't, 'cause the struct is stored on the stack, so once your program ends or the function returns, it'll ge destroyed automatically. And, oh yeah, next time use the "" tags when posting code. Or just put the .cpp file as an attachment if the code is *really* long.

Thank you. Got it.

Well...the rule of thumb is pretty easy...you have to release memory if

• it was allocated with 'new'/'new []'
• it was allocated with 'malloc()'/'calloc()'
• the specification of the function explicitly states it