Polymorphism .. override

When you override a virtual function of a base class .. do you have to call the base class method ? Always ?

I've tested with Visual Studio .. as i type override .. it automatically call the base class virtual function.

Why ???? is it like that ?

I mean ... whatever the implementation of the virtual function of the base class .. that implementation will be called ... but why should i ? I want my own implementation to be used only ....

Thanks,

i guess i could take it off, but i've seen alot of examples doing it, calling the base method in the override implementation. But why?

Can virtual be protected ?

Quote:

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Originally Posted by Mattrang

Can virtual be protected ?

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In C# there's no such thing as access modifier on inheritance .. not like c++.

I know in c++ youd do class A : public B

but in C# its

class A : B

EDIT : OH sorry i think you meant if you can declare a virtual method as protected ? The answer to that is NO.

Quote:

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Originally Posted by Mattrang

Can virtual be protected ?

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If protected, then no override is allowed

Quote:

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Originally Posted by GoDaddy

When you override a virtual function of a base class .. do you have to call the base class method ? Always ?

I've tested with Visual Studio .. as i type override .. it automatically call the base class virtual function.

Why ???? is it like that ?

I mean ... whatever the implementation of the virtual function of the base class .. that implementation will be called ... but why should i ? I want my own implementation to be used only ....

Thanks,

---

Your inheritance hierarchy might have some problem

PHP Code:

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class Base{
    public virtual void funfoo(){
        Console.WriteLine("funfoo Base");
    }
}

class Derive1 : Base{
    public override void funfoo(){
        Console.WriteLine("funfoo Derive1");
    }
}

class Derive2: Derive1{
    public override void funcfoo(){
        Console.WriteLine("funfoo Derive2");
    }
}

class AfterAll{
    public static void Main(string[] args)
    {
        Base b  = new Base();
        Base d1 = new Derive1();
        Base d2 = new Derive2();
              
        b.funfoo(); //Only this one calls the base class
        d1.funfoo();
        d2.funfoo();
        
        
        Derive1 d01 = new Derive1();
        Derive2 d02 = new Derive2();
        
        
        d01.funfoo();
        d02.funfoo();
    }
} 


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I meant that when i try to override a virtual function of a base class, Visual studio will do a autocomplete like this

Code:

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public override void foo()
{
    base.foo() //This part is generated automatically by VS.NET .. but why???? do i needed?
}

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Quote:

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Originally Posted by GoDaddy

I meant that when i try to override a virtual function of a base class, Visual studio will do a autocomplete like this

Code:

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public override void foo()
{
    base.foo() //This part is generated automatically by VS.NET .. but why???? do i needed?
}

---

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Ohhh...,
I guess it is based on the understanding of object architecture, MS people may think it is a base class ctor that should be auto-generated during coding stage to, at the same time, remind end-users or coders what is overriden. It may seem to be irrelevent to many people but such a feature doesn't bug the application anyway.
Auto-generating code on coding editors is not new at all, but other people may offer you other ideas on how such code snip is auto-created if you still want to understand..

Thanks :D

So i don't need it ....

Quote:

---

Originally Posted by Mattrang

Can virtual be protected ?

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Yes it can!!!
For example:

Code:

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class Base
{
        protected virtual void foo()
        {
               
        }
}

class Derived:Base
{
        protected override void foo()
        {
                base.foo ();
        }

}

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This code works.