Need help with arrays

I'm trying to write this program which doesn't yield the output desired.

Here's the prompt:
Write a C++ program that declares an array alpha of 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the index variable and the last 25 components are equal to three times the index variable. Then just output the array.

Here's what I have:

#include <iostream>
using namespace std;

int main(){
double alpha[50];
int counter;
int square;
int times3;
for(counter = 0; counter <= 24; counter++)
{
square = counter * counter;
square = alpha[counter];

}

for(counter = 25; counter <= 49 && counter > 24; counter++)
{
times3 = counter * 3;
times3 = alpha[counter];
}

for(counter = 0; counter <= 49; counter++)
{
cout << " ";
cout << alpha[counter];
}
}

How about this

Code:

---

#include <iostream>
using namespace std;

int main(){
double alpha[50];
int counter;
for(counter = 0; counter <= 24; counter++)
{
alpha[counter]=counter*counter;
}

for(counter = 25; counter <= 49; counter++)
{
alpha[counter]=3*counter;
}

for(counter = 0; counter <= 49; counter++)
{
cout << " ";
cout << alpha[counter];
}
}

---

Thanks! Now I see where my problem was. It was a mistake I should have learned not to make by now.

The statement

square = alpha[counter]

makes no sense. You must have alpha[counter] before the assignment statement because it's evaluated from right to left and you want square's value to be copied into the array alpha.

The same is true for several other statements in my code.

more compact version, behnood, to show u where u can save code lines

Code:

---

#include <iostream>
using namespace std;

int main () {
        double alpha[50];

        // i^2
        for (int i = 0; i < 25; ++i) // note the < 25 this is the same as <= 24 but the more common way
                alpha[i] = i * i;

        // 3*i
        for (int i = 25; i < 50; ++i)
                alpha[i] = i * 3;

        // print
        for (int i = 0; i < 50; ++i)
                printf ("%d\n", alpha[i]);
}

---