fopen vs. fopen64

Hello

To be able to open large logfiles in a software, I change the necessary "fopen"-command to "fopen64". This procedure works and is described in a patch, too. However when I compile it I get some warnings:
--> In function `main':
--> warning: implicit declaration of function `fopen64'
--> warning: assignment makes pointer from integer without a cast

Before patching I had:

Code:

---

FILE    *log_fp;
...
log_fp = fopen(log_fname,"r");

---

After patching:

Code:

---

FILE    *log_fp;
...
log_fp = fopen64(log_fname,"r");

---

How can I avoid that warning???

Quote:

---

Originally Posted by frei

Hello

To be able to open large logfiles in a software, I change the necessary "fopen"-command to "fopen64". This procedure works and is described in a patch, too. However when I compile it I get some warnings:
--> In function `main':
--> warning: implicit declaration of function `fopen64'
--> warning: assignment makes pointer from integer without a cast

Before patching I had:

Code:

---

FILE    *log_fp;
...
log_fp = fopen(log_fname,"r");

---

After patching:

Code:

---

FILE    *log_fp;
...
log_fp = fopen64(log_fname,"r");

---

How can I avoid that warning???

---

I assume you are using C rather than C++. In C, if you call an undeclared function, the compiler assumes it returns an int, and then complains that you are converting the int to a pointer. The fopen64 routine is specific to Linux; if that is what you are using, make sure you are including the righr headers.

Hope that helps.

Yes, I'm using C, not C++.

The function is declared: I have the stdio.h header included (#include <stdio.h>).

The program works, but I get the above warnings when I use fopen64 instead of fopen...

I really don't know why... Does someone have an idea to get rid of the problem??

You need to compile with -D_LARGEFILE64_SOURCE option.