another float/int/for question

Hello I have a loop like this:

int j;
for(float i = 0.0f, j = 0; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))
intervalEdges.push_back(j);

For some reason when I look at "j" value it is represented as a floating point number.

Any idea why? Is this the best way to try to do something like this??

Thanks!

'for' begins another scope, allowing you to hide outer-scope variables.
'float i = 0.0f, j = 0;' defines two floats, i and j.

solution: set j = 0 before the loop:

Code:

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int j = 0;
for(float i = 0.0f; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))

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Jeff

Did you put the brace in the right place? I guess

Code:

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for(float i = 0.0f; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))

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should be

Code:

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for(float i = 0.0f; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION), j++)

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Besides, you don't need the loop, and intervalEdges container perhaps:
you need to know what is the upper-bound of j right? [0, x], need to know x.
set a = 1.0f/CDF_RESOLUTION
x = int((1.0f - 0.0f)/a);

Quote:

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Originally Posted by lab1

Hello I have a loop like this:

int j;
for(float i = 0.0f, j = 0; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))
intervalEdges.push_back(j);

For some reason when I look at "j" value it is represented as a floating point number.

Any idea why? Is this the best way to try to do something like this??

Thanks!

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This is not part of your subject line, but there are far more worse issues with this code that were discussed here already.

http://www.codeguru.com/forum/showthread.php?t=408602
https://www.securecoding.cert.org/co...+loop+counters
http://www.math.ucsd.edu/~sbuss/Cou...atingperils.pdf

Regards,

Paul McKenzie