getting average!!

hi im stuck.
lets say i have
int count =6;
and make and array of
float n[6]={1,2,3,4,5,6},total,average;
and i want it to add all the numbers up
How would i do this in a loop?
NOT this way
n[0]+n[1]+n[2]+.... then /count

Code:

---


float sum = 0;
float n[6]={1,2,3,4,5,6}

for( int i = 0; i<count; ++i)
{
    sum += n[i];

}

float average = sum/count;

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Good luck!

Gili

thnx its working fine now

Or, with the use of accumulate

Code:

---

#include <algorithm>

float n[6]={1,2,3,4,5,6}
float sum = std::accumulate(&n[0], &n[5], 0);
float avg = sum / 6;

---

Hello,

It is advantageous to use STL where the size of the array is bound with the data itself. Here is a sample code to evaluate the average of a vector array.

Code:

---

float average(std::vector<float> array)
{
        float sum = 0;
        for (int count = 0; count < array.size(); count++)
                sum += array[count];
        return sum / array.size();
}

---

Regards,
Pravin.

Quote:

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Originally Posted by Pravin Kumar

Hello,

It is advantageous to use STL where the size of the array is bound with the data itself. Here is a sample code to evaluate the average of a vector array.

Code:

---

float average(std::vector<float> array)
{
        float sum = 0;
        for (int count = 0; count < array.size(); count++)
                sum += array[count];
        return sum / array.size();
}

---

Regards,
Pravin.

---

I suggest passing the vector by reference to avoid making a useless copy (especially if the vector holds many elements).

Quote:

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Originally Posted by cilu

Or, with the use of accumulate

Code:

---

#include <algorithm>

float n[6]={1,2,3,4,5,6}
float sum = std::accumulate(&n[0], &n[5], 0);
float avg = sum / 6;

---

---

1) accumulate is in <numeric>
2) the "end()" iterator has to be one past the last element

Code:

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float sum = std::accumulate(&n[0], &n[6], 0); // or (n,n+6,0.0f)
float avg = sum / 6;

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