Is there a way to cast a char to a string?

Hello everyone, I havn't been doing C++ in awhile but I need to freshen up fast!

I'm doing the following,

I'm trying to see if somthing in string2 is in string1,
for example string2 is "eo"
String1 = "Hello"
Hello has
both an e and an o
the logic to see if "eo" in "Hello" works but once I find that yes there is an e and an o in "Hello" I want to remove the e and o, so the string remaining is
hll

Well the replace function only accepts STRINGS so I was trying to cast the character e when its found to a string, then using the string.repalce(i,1,char1);

But I keep getting that error any ideas?

Code:

---

#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;




int main()
{

        string string1 = "Hello";
        string string2 = "eo";
        cout << "string1: " << string1 << endl;
       
        for(int i = 0; string1[i] != '\0'; i++)
        {
                if(string1[i] == string2[0])
                {
                        cout << "found: " << string2[0] << " in the string: " << string1 << endl;
                        //string1[i] = string1[i+1];
                        string char1 = string2[0];
                        string1.replace(i,1,char1);
                }
                else if(string1[i] == string2[1])
                {
                        cout << "found: " << string2[1] << " in the string: " << string1 <<  endl;
                        //string1[i] = string1[i + 1];
                        string char2 = string2[1];
                        string1.replace(i,1,char2);
                }
                else
                        cout << "nothing in string2: " << string2 << "matches in string1: " << string1 << endl;
        }
        cout <<"New string: " << string1 << endl;

        return 0;
}

---

The error is:

Quote:

---

1>.\test.cpp(22) : error C2440: 'initializing' : cannot convert from 'char' to 'std::basic_string<_Elem,_Traits,_Ax>'
1> with
1> [
1> _Elem=char,
1> _Traits=std::char_traits<char>,
1> _Ax=std::allocator<char>
1> ]
1> No constructor could take the source type, or constructor overload resolution was ambiguous
1>.\test.cpp(29) : error C2440: 'initializing' : cannot convert from 'char' to 'std::basic_string<_Elem,_Traits,_Ax>'
1> with
1> [
1> _Elem=char,
1> _Traits=std::char_traits<char>,
1> _Ax=std::allocator<char>
1> ]
1> No constructor could take the source type, or constructor overload resolution was ambiguous
1>Build log was saved at "file://c:\Documents and Settings\Mr. Coffee\My Documents\Visual Studio 2005\Projects\C program\C program\Debug\BuildLog.htm"
1>C program - 2 error(s), 0 warning(s)
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

---

Strings can be constructed from chars. For example, here glGetString returns a char*, so ext is a std::string from a function that returns char*.

Code:

---

string ext ((const char*)glGetString(GL_EXTENSIONS));

---

Viceversa, c_str method of C++ strings can be used to convert a std::string to a C standard char* type.

It seems I don't need to do that at all but the problem I'm having now is how do I delete the last character of this string without an overflow?

I'm telling it to delete the o off hello, and its mad because the '\0' is next, but I'm not telling it to delete the '\0' so I don't understand why its upset.

I get a runtime error if I use this code:

Code:

---

#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;




int main()
{

        string string1 = "Hello";
        string string2 = "eo";
        cout << "string1: " << string1 << endl;
       
        for(int i = 0; string1[i] != '\0'; i++)
        {
                if(string1[i] == string2[0])
                {
                        cout << "found: " << string2[0] << " in the string: " << string1 << endl;
                        //string char1 = string(&string2[0],1);
                        string1.erase(i,1);
                }
                else if(string1[i] == string2[1])
                {
                        cout << "found: " << string2[1] << " in the string: " << string1 <<  endl;
                        //string char2 = string(&string2[1],1);
                        string1.erase(i,1);
                }
                else
                        cout << "nothing in string2: " << string2 << "matches in string1: " << string1 << endl;
        }
        cout <<"New string: " << string1 << endl;

        return 0;
}

---

If i comment out the last erase it will return
Hllo
but i want it to delete the o so its
Hll


Also this was what I used to convert a character to a string, but it wasn't needed.
string char1 = string(&string2[0],1);

Why can't you use CString::Remove()

Code:

---

CString str("hello");
int n = str.Remove('e');
n = str.Remove('o');

---

when you say CString do you mean <string> or is there an actual library called CString?

Cstring is different from string. string (std::string) is one of the standard template library, whereas CString is a COM pointer to the character string, i.e., the character string is wrapped in a component. For using CString, you should use MFC

Hi,

Try this:

Code:

---

string string1 = "Hello";
string string2 = "eo";
cout << "string1: " << string1 << endl;

string::iterator iter = string1.begin();

while (iter != string1.end() )
{
        char ch = iter[0];       
               
        if (ch == string2.at(0) || ch == string2.at(1))
        {
                string1.erase(iter);
                continue;
        }

        iter++;
}

cout<<"New string : "<<string1<<endl;

---

There's this thing called remove_if (among other useful things). Use it.

Code:

---

#include <algorithm>
#include <string>

struct Remove
{
    Remove(const std::string& garbage) : garbage_(garbage)
    {
    }

    bool operator()(std::string::value_type symbol) const
    {
        return garbage_.find(symbol) != std::string::npos;
    }

    const std::string garbage_;
};

int main()
{
    std::string string1 = "Hello";

    string1.erase(std::remove_if(string1.begin(), string1.end(), Remove("eo")), string1.end());   
}

---