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Write a Program in C++ that take input of the number from User and print this number its English number.
Sample Output:
Enter any number: 52
Number you enter is Fifty Two
Note:
You can use only and only if condition.
Range of number can be from 0 to 99.
The Problem is I Have to Use IF Condition and some Efficient Way, like not 100 comparisons...
I just Want to need help or hint in its algo or logic so i can make it in C++.
With Many Thanks.
1) Create an array of names up to the word "nineteen":Quote:
Originally Posted by butt_usman
"zero", "one", "two", "three", ... "nineteen"
2) Create another array with the words "twenty", "thirty", up to "ninety".
"twenty", "thirty", "forty", "fifty", ... "ninety"
3) If the number is less than 20, use the value as an index in the first array, and you have the answer.
4) If the number is greater than or equal 20,
a) divide the number by 10 to get the left digit. That number minus 2 is an index into the second array.
b) Do mod 10 on the original number to get the remainder. This will be the right digit. If the right digit is greater than 0, this is the index in the first array of the name.
For example:
Example 1:
Input: 4
array1[4] = "four" (finished)
Example 2:
Input: 35
this is greater than 20. So divide by 10:
35 / 10 = 3
array2[3-2] = array2[1] = "thirty".
Do a mod 10 on 35:
35 mod 10 = 5.
Since 5 is greater than 0, this is the index in the first array:
"thirty" array1[5]
"thirty" "five" -> thirty five.
Regards,
Paul McKenzie
Thanks Alot Man, It Really Helped Alot, Actually the Algorithm i Selected was using more Comparisons, ALthough Array can shorten it , but i m forced to use ONLY IF Conditions..
Mods can Close the Topic !
What does if() conditions have to do with arrays?Quote:
Originally Posted by butt_usman
That's like saying "I can only use a car, but not drink water". Driving a car and drinking water have nothing to do with each other.
Regards,
Paul McKenzie