How to print total memory allocated for an object

Hi,
class Sample
{
int x, *ptr;
public:
Sample()
{
ptr = new int[100];
}
~Sample()
{
}
};
int main()
{
cout << "SizeofClass" << sizeof(Sample); //gives me output 8
Sample sm;
cout<< "SizeofObject" << sizeof(sm); //also gives me output 8


}

But i assume the size of sample object should be 4(x) + 400(ptr) = 404 bytes

Is there anyway that i can know or print the total memory alloacted which

x + ptr = 4 +400 = 404 bytes

Is my assumption correct ? Pls clarify me on this

Thanks
Kiran

It is not possible by any standard means. You'd have to either implement your solution based on size tracking of all dynamically allocated objects, or use some platform dependent ways (_msize for heap arrays, etc.)

Cheers

So, is it mean the size of an object is always caluculated at compile time irrespective of whether it contains a normal member variable or pointer variables ?

Any exception is there for this case ?

Quote:

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Originally Posted by rsodimbakam

So, is it mean the size of an object is always caluculated at compile time irrespective of whether it contains a normal member variable or pointer variables ?

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Yes. The sizeof() is a compile-time constant.

Quote:

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Any exception is there for this case ?

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No.

Regards,

Paul McKenzie

Quote:

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But i assume the size of sample object should be 4(x) + 400(ptr) = 404 bytes

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In that particular example the actual memory used would be

sizeof(int) + sizeof(int*) + sizeof(int)*100

which is,

x + ptr + (memory allocated to ptr)

+ any padding the compiler decides to add to the struct