pointer

Hi, all

If I have array:

float* p ;
p = (float*) malloc( sizeof(float) * 10)

and I have a function that give me two numbers each time I call it

If I want to call this function 5 times, how do I save these 10 value outputs sequentially into my array p buy just put my array into the function ?

like:

for( int i=0; i<5; i++ )
{
myfunction (A, B, *p) ;
}



THX

Quote:

---

Originally Posted by kiani45

Hi, all

If I have array:

float* p ;
p = (float*) malloc( sizeof(float) * 10)

and I have a function that give me two numbers each time I call it

If I want to call this function 5 times, how do I save these 10 value outputs sequentially into my array p buy just put my array into the function ?

like:

for( int i=0; i<5; i++ )
{
myfunction (A, B, *p) ;
}
THX

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Code:

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#define ARRAY_SIZE 10
int nIndex;
float* p;
void myfunction(float a,float b,float* p)
{
 if (nIndex < ARRAY_SIZE-2) {
  p[nIndex]=a; nIndex++;
  p[nIndex]=b; nIndex++;
 }
}

int main()
{
  nIndex=0;
  p=(float*)malloc(sizeof(float)*ARRAY_SIZE);
  ..............................
  myfunction(A,B,p);
  ..........
}

---

Have a good time

This looks like C

Quote:

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Originally Posted by kiani45

float* p ;
p = (float*) malloc( sizeof(float) * 10)

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If you want to use C++

Code:

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std::vector<float> p(10);

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Code:

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#include <stdio.h>
#include <stdlib.h>

void myfunction(int &A, int &B, float *p)
{
        static a=0,b=0;
        A = ++a;
        B = ++b + a;

        *p = A;
        *(p+1) = B;
}

int main()
{
        float *p, *pOld;
        p = (float*) malloc( sizeof(float)* 10 );
        pOld = p;


        int A,B;
        for( int i=0; i<5; i++ )
        {
                myfunction(A, B, p);
                p+=2;
        }

        p = pOld;
        for( int j=0; j<10; j++ )
        {
                printf("&#37;f\n", *(p++));
        }

        free(pOld);
        return 0;
}

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