Copy 2 Strings in a third string

hi folks

i have problem

i want to copy String_A and String_B in String_C

how can i make this????

after copy the String_C should look like STRING_ASTRING_B

the source i've tried looks like....


int SadClass::Add_To_SadString()
{
char * StringA=NULL;

if(StringC!=NULL)
{
StringA= new char[StringSize*CountRecord];

strcpy(StringA,StringC);

delete StringC;
}

StringC= new char[(int)StreamSize];

if(StringA!=NULL)
{
strcpy(StringC,StringA);

delete StringA;
}

strncpy(StringC + CountRecord * StringSize,StringB ,(int)StreamSize);


CountRecord++;

return 0;
}





please HELP.....

thanks

Are the strings defined as CStrings or arrays of characters?

If they are CStrings you should be able to do something like this:

String_C = String_A + String_B;

or

String_C = String_A + " " + String_B;

If they are arrays of characters try something like this:

strcpy(String_C, String_A)
strcat(String_C, String_B);

Hope this helps.

Use strcat

Really it depends on what kind of strings you are using. If you are using CStrings simply use the + or += operator

CString a = "Hello";
CString b = "World";
CString c;
CString d = "Momma";

c = a+b; // sets c to "Hello World"
a += d; // set a to "Hello Momma"

If you are using generic character pointers you need to use the strcat function.

char* a = "Hello";
char* b = "World";
char* c;
strcpy (c,a); //sets c to "Hello"
strcat (c,b); // sets c to "Hello Word"

Finally if you are using character arrays you can do the same thing by extending the size of your array, then copying the characters from the other array over.

Make sure that you are careful not to overwrite memory as this would cause problems.

Rob P.

thanks allot

the command strcat was new for me.

now it works.

thank you

the command strcat was new for me.

now it works.

thank you peter

it was very helpfull

the command strcat was new for me.

thanks

char* a = "Hello";
char* b = "World";
char* c;
strcpy (c,a); //sets c to "Hello"
strcat (c,b); // sets c to "Hello Word"

doesn't work that well, as char* c doesn't have memory allocated to it

sally