i tried(((

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i did as u told me and i have two errors
**Error** zz.ASM(1) Unknown character
**Fatal** zz.ASM(76) Unexpected end of file encountered.
this is d new code:
CLEAR MACRO COLOR ;Î÷èñòêÃ* ýêðÃ*Ã*Ã* öâåòîì
MOV AX, 0600H ;Ã�ðîêðóòêÃ* âñåãî ýêðÃ*Ã*Ã*
MOV BH, COLOR
XOR CX, CX
MOV DX, 184FH
INT 10H
ENDM

TEXTOUT MACRO TEXT ;Âûâîä òåêñòÃ* ÷åðåç ôóÃ*êöèþ 9 ïðåðûâÃ*Ã*èÿ

21H
MOV AH, 09
LEA DX, TEXT
INT 21H
ENDM

TEXTIN MACRO BUF ;Ââîä òåêñòÃ* ÷åðåç
MOV AH, 0AH
LEA DX, BUF
INT 21H
ENDM

StackS SEGMENT PARA STACK 'STACK'
DW 32 DUP(?)
StackS ENDS


MAX_TEXT EQU 80
DATA SEGMENT PARA PUBLIC 'DATA'
MESS1 DB 0AH,0DH,"Ââåäèòå ñòðîêó: $"
MESS2 DB 0AH,0DH," ìÃ*ëåÃ*üêèõ áóêâ: $"


BUF1 DB MAX_TEXT
QNT1 DB 0
TEXT1 DB MAX_TEXT DUP(?)


DATA ENDS

CODE SEGMENT PARA PUBLIC 'CODE'
ASSUME CS:CODE, DSATA, SS:StackS

START: MOV AX, DATA ; çÃ*ãðóçèòü â DS
MOV DS, AX ;ñåëåêòîð ñåãìåÃ*òÃ* äÃ*Ã*Ã*ûõ
MOV ES, AX
CLEAR 30
TEXTOUT MESS1
TEXTIN BUF1
TEXTOUT MESS2 ; output the message "output: "

XOR CH, CH ;Îáíóëåíèå ñòàðøåãî áàéòà ñ÷åò÷èêà
MOV CL, QNT1 ;Çàãðóçêà êîëè÷åñòâà ñèìâîëîâ â ñòðîêå
LEA SI, TEXT1 ;Àäðåñ îñíîâíîé ñòðîêè â èñòî÷íèê
CLD

print_upper: lodsb ; Get next char in str. *
cmp al, "a" ; if < 'a', just print it
jb print_it
cmp al, "z" ; if > 'z' just print it
ja print_it
sub al, 20h ; if lower case a - z, make it upper
print_it:
call putc ; display the letter
loop print_upper

mov ax, 4c00h
int 21h ; return to ms-dos

putc: ; display character in dl
mov dl,al
mov ah, 2h
int 21h
ret

CODE ENDS
END START

and cn u explain to me how to count d lines so i cn trace d errors

Based on the non-english texts and comments you have, I tried to save the file with UNICODE encoding then compiled it, and I got the "Unexpected end of file encountered" :) The "unknown character" could be due to the language id you are using. To fix it, save the file using ANSI or UTF-8 encoding.

I'm using Notepad2. It has line indicator so you don't need to count the number of lines.

Hope it will work for you :)

thanks so much its ok.i have so many things to learn in assembly language and i rily appreciate ur help.
but i still got more things:).
i showed the fist program i did that is the one that counts the number of occurences of a character in a string to my teacher and he says it is correct but i should write it in a diferent way:(.he referred to the REPNE SCASB line and said i shud write it in a different way:).he also said i shud write the program in such a way that i dnt have to input with the keyboard.meaning the program is jud=st gonna run itself.
here is d code:
CLEAR MACRO COLOR
MOV AX, 0600H
MOV BH, COLOR
XOR CX, CX
MOV DX, 184FH
INT 10H
ENDM

TEXTOUT MACRO TEXT ;string output using the function 21H
MOV AH, 09
LEA DX, TEXT
INT 21H
ENDM

TEXTIN MACRO BUF ;string input
MOV AH, 0AH
LEA DX, BUF
INT 21H
ENDM

StackS SEGMENT PARA STACK 'STACK'
DW 32 DUP(?)
StackS ENDS


MAX_TEXT EQU 80
DATA SEGMENT PARA PUBLIC 'DATA'
MESS1 DB 0AH,0DH,"input string: $"
MESS2 DB 0AH,0DH,"input letter: $"
MESSNOT DB 0AH,0DH,"letter not found.$"
MESSYES DB 0AH,0DH,"it contains $ "

BUF1 DB MAX_TEXT
QNT1 DB 0
TEXT1 DB MAX_TEXT DUP(?)

DATA ENDS

CODE SEGMENT PARA PUBLIC 'CODE'
ASSUME CS:CODE, DS:DATA, SS:StackS

START: MOV AX, DATA ;load into DS
MOV DS, AX ;selects the given segment
MOV ES, AX

CLEAR 30
TEXTOUT MESS1
TEXTIN BUF1
TEXTOUT MESS2
MOV AH,1
INT 21H

XOR CH, CH ;clears upper bite
MOV CL, QNT1 ;loads the number of symbols into the substring
JCXZ NOTFOUND ;empty string is a part of string
LEA DI, TEXT1 ;address of the substring in source input
XOR BX,BX
CLD ;sets the flag in the direction of ascending order

NEXT:
*REPNE SCASB ; continuously scan until a match is found or CX is 0
*JNE CONTINUE ; if no match, goto show the result
*ADD BX,1 ; if match, increment our count
*JCXZ CONTINUE ; if nothing more to process, goto show the result
*JMP NEXT ; otherwise, continue with our loop

*CONTINUE:

*CMP BX,0 ;compare string
*JE NOTFOUND

PUSH BX ; save our count into the stack
TEXTOUT MESSYES
POP AX ; put the count (from the stack) to AX

; PRINT the value of AX

mov bx, sp
divide_by10:
xor dx, dx
mov cx, 10
div cx
push dx
or ax, ax
jnz divide_by10
print_result:
mov ah, 2
pop dx
add dl, '0'
int 21h
cmp sp, bx
jne print_result

JMP EXIT

NOTFOUND:
TEXTOUT MESSNOT

EXIT: XOR AL, AL
MOV AH, 4CH
INT 21H
CODE ENDS
END START
he askd me to rewrite the parts i marked with asteriks in the program.

secondly he askd me to write another program that puts a frame around a string wen i input with the keyboard.
example: hello
wud appear on the screen as *******
*hello *
***** *
the size of the frame changes with the lenght of the word inputed.
thks:)))

Did he tell you why REPNE SCASB should not be used? Is there something wrong with it? :D Anyway you can check the input 1 by 1 incrementing the pointer in every iteration

Code:

---

XOR CH, CH
MOV CL, QNT1
JCXZ NOTFOUND
LEA DI, TEXT1
XOR BX,BX
CLD

COMPARE_IT:
  cmp al, [di]      ; compare AL with the byte in [di]
  jne NEXT_CHAR    ; if NOT match, goto next character
  inc bx            ; if match, increment our count
NEXT_CHAR:
  inc di            ; increment our pointer
  loop COMPARE_IT  ; loop until CX == 0
 
;NEXT:
;REPNE SCASB        ; continuously scan until a match is found or CX is 0
;JNE CONTINUE        ; if no match, goto show the result
;ADD BX,1            ; if match, increment our count
;JCXZ CONTINUE      ; if nothing more to process, goto show the result
;JMP NEXT            ; otherwise, continue with our loop

;CONTINUE:

CMP BX,0
JE NOTFOUND

---

If you want the string input to be hard coded, you can preset your QNT1 and TEXT1 and remove the TEXTIN. For example the string is "testing"

Code:

---

QNT1 DB 7
TEXT1 DB "testing"

---

This way you don't need to change the way you process the string.

For printing the string with '*' frame. Since you can get the length of the input string, just output '*' for len + 2 (1 in front and 1 at the back of the input) in the first line. For the second line, output '*' and then the string and finally the '*' at the back. The 3rd line would be the same as the first line.

thanks so much for ur help.i worked on inputing d string hard coded and it was working well.but wen i tired on working on the input of the string to be compared als to b hard coded,its not working correctly.i need to write d program in a way such dat everything is hard coded.this is what i have written can u tell me wat isnt right cos it keeps showing me letter not found after i press the enter key wen i run he program.



CLEAR MACRO COLOR
MOV AX, 0600H
MOV BH, COLOR
XOR CX, CX
MOV DX, 184FH
INT 10H
ENDM

TEXTOUT MACRO TEXT
MOV AH, 09
LEA DX, TEXT
INT 21H
ENDM

TEXTIN MACRO BUF
MOV AH, 0AH
LEA DX, BUF
INT 21H
ENDM

StackS SEGMENT PARA STACK 'STACK'
DW 32 DUP(?)
StackS ENDS



DATA SEGMENT PARA PUBLIC 'DATA'


MESSNOT DB 0AH,0DH,"letter not found.$"
MESSYES DB 0AH,0DH,"it contains $"

BUF1 DB "x"
QNT1 DB 7
TEXT1 DB "tsdfaxc"

DATA ENDS

CODE SEGMENT PARA PUBLIC 'CODE'
ASSUME CS:CODE, DS:DATA, SS:StackS

START: MOV AX, DATA
MOV DS, AX
MOV ES, AX

CLEAR 30
TEXTIN BUF1
MOV AH,1
INT 21H

XOR CH, CH
MOV CL, QNT1
JCXZ NOTFOUND
LEA DI, TEXT1
XOR BX,BX
CLD

COMPARE_IT:
cmp al, [di] ; compare AL with the byte in [di]
jne NEXT_CHAR ; if NOT match, goto next character
inc bx ; if match, increment our count
NEXT_CHAR:
inc di ; increment our pointer
loop COMPARE_IT

CMP BX,0
JE NOTFOUND

PUSH BX
TEXTOUT MESSYES
POP AX


mov bx, sp
divide_by10:
xor dx, dx
mov cx, 10
div cx
push dx
or ax, ax
jnz divide_by10
print_result:
mov ah, 2
pop dx
add dl, '0'
int 21h
cmp sp, bx
jne print_result

JMP EXIT

NOTFOUND:
TEXTOUT MESSNOT

EXIT: XOR AL, AL
MOV AH, 4CH
INT 21H
CODE ENDS
END START

i also need help in the second question i asked about printing out a string with a framed(*).
example:hello
on the screen ******
*hello*
******
the size of the frame increases wtih the sizze of the string.i have bn tying to write the program but i cnt figure anything out:( plas i need help

You get the "letter not found" error because you are still using the TEXTIN macro w/c will overwrite the content of your BUF1. You have to remove the TEXTIN in your code.

To hardcode the character to compare you have to remove the interrupt 21 function 01 and hardcode the character in AL.