Get the Maximum Value from a List

Well guys, I have variable-sized List and I have populated it with double values...

List<double> tempAvg = new List<double>();

I want to know the Maximum value within the List. I thought first to sort the List and then get the last index, but I dont know how to do that.

any Idea?

There is Array.Sort() method, if you are using fx3.5 with LINQ, you can use Max() extension method directly.

Use the Sort method that built into the List. You will have to do a custom sor to get the list in the descending order, something like this

Code:

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            List<double> tempAvg = new List<double>();
            tempAvg.Add(12.90);
            tempAvg.Add(2.90);
            tempAvg.Add(13.90);
            tempAvg.Add(1.90);
            tempAvg.Sort(delegate(double d1, double d2)
            {
                return d2.CompareTo(d1);
            });
            Console.WriteLine(tempAvg[0].ToString());

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Thank you very much, it was very helpful.

Quote:

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Originally Posted by boudino

There is Array.Sort() method, if you are using fx3.5 with LINQ, you can use Max() extension method directly.

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I just tried the extension method in 3.5 and it works like a charm. Thanks :thumb:

Code:

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//top of the module
using System.Linq;

//all other code
            List<double> tempAvg = new List<double>();
            tempAvg.Add(12.90);
            tempAvg.Add(2.90);
            tempAvg.Add(13.90);
            tempAvg.Add(1.90);
            Console.WriteLine(tempAvg.Max().ToString());

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