Problem: Release mode versus Debug mode and using COUT resolves it

I have the following function

void Schedule::fillUpHomeAwayArray(fixture *s_, int idx, int teamsInDiv, int *homeTeamList, int *awayTeamList) {

int curDiv = s_[idx].div_;
int curTeam = s_[idx].homeID_;
int listIdx = 0;
int *curList = homeTeamList;
curList[listIdx] = curTeam;
listIdx++;

while(s_[idx].div_ == curDiv) {
// ** cout << idx << endl;
if(curTeam != s_[idx].homeID_) {
curTeam = s_[idx].homeID_;
curList[listIdx] = curTeam;
listIdx++;
}

if(listIdx == teamsInDiv / 2) {
curList = awayTeamList;
listIdx = 0;
}
idx++;

} // while


}


It works fine (as expected) in Debug mode (I am using VC++ vers 6).

But when I run it in release mode, I don't get the same results. It looks as if idx is taking on strange values, and so the values returned are uninitialised.

BUT, if I uncomment the cout (see line // **), it works in release mode, the same as in debug mode.

Two questions.

1. Why does it work in debug mode and not release.
2. Why does adding the cout make it work in release mode.

Thanks

can you give smallest, complete compilable code that will reproduce the code please?

please explain how the results are different.

Quote:

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Originally Posted by gxkendall

But when I run it in release mode, I don't get the same results. It looks as if idx is taking on strange values, and so the values returned are uninitialised.

BUT, if I uncomment the cout (see line // **), it works in release mode, the same as in debug mode.

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It doesn't "work" in any mode, release, debug, or in between.

The program has a bug. It just so happens that the bug is exposed when you run the program a certain way or change it by adding (or removing) superfluous lines of code.

Quote:

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Two questions.

1. Why does it work in debug mode and not release.

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Anything you do with pointers or arrays that result in undefined behavior results in programs running erratically. No one knows what those values are that you're sending to the function, whether the values are initialized, how those functions are called, etc.

Quote:

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2. Why does adding the cout make it work in release mode.

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See first paragraph. The program never works. All you're doing is moving the bug to another part of your program when you add or remove code.

Regards,

Paul McKenzie