Zeller's Congruence

The error i keep getting is

27 ..\p2\dayCount.cpp expected `)' before numeric constant

Anyone able to give me some insight into this?

#include <iostream>
#include <cmath>
using namespace std;

int main(){
//user input
int q; // q = day of the month (1-31)
int m; // m = month (3 = March, 4 = April, 5 = May, 6 = June, 7 = July, 8 = August, 9 = September, 10 = October, 11 = November, 12 = December, 13 = Janurary, 14 = February)
int y; // Year ####
//calculated values
int k; // k = year of the century
int j; // j = century (For example, in 1995 the century would be 19, even though it was the 20th century.)
//After complet Calculations
int h; // h = day of the week (0 = Saturday, 1 = Sunday, 2 = Monday, 3 = Tuesday, 4 = Wednesday, 5 = Thrusday, 6 = Friday)

cout << "Enter the Day of the Month (1-31): ";
cin >> q;
cout << endl;
cout << "Enter the Month: " << endl;
cout << "3 = March, 4 = April, 5 = May, 6 = June, 7 = July, 8 = August, 9 = September, 10 = October, 11 = November, 12 = December, 13 = Janurary, 14 = February" << endl;
cin >> m;
cout << endl;
cout << "Enter the Year: ";
cin >> y;
cout << endl;

h = ( q + floor( ((m+1)26) / 10 ) + y + floor(y/4) + 6 * floor(y/100) + floor(y/400)) % 7;

cout << h;

system("pause");
return 0;
}

Looks like the problem is ((m+1)26). Possibly need a arithmetic operator between the right paren and 26???

Code:

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h = ( q + floor( ((m+1)26) / 10 ) + y + floor(y/4) + 6 * floor(y/100) + floor(y/400)) % 7;

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AFAIK, we does not need any formula to calculate day of week.

You can use computation logic with the help of array.

Quote:

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Originally Posted by BobS0327

Looks like the problem is ((m+1)26). Possibly need a arithmetic operator between the right paren and 26???

Code:

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h = ( q + floor( ((m+1)26) / 10 ) + y + floor(y/4) + 6 * floor(y/100) + floor(y/400)) % 7;

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All the variables are already ints so using the floor() function is redundant. You also might want to look into putting some error guards in against invalid dates like February 29 in a non-leap year, or September 31.

Out of curiosity...what is the reason behind the non-standard numeric assignment of the weekdays and months?

C FAQ Zeller Conguence

Code:

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#include <iostream>
#include <cmath>
#include <stdio.h>
using namespace std;

int main(){
    //user input
    int q; // q = day of the month (1-31)
    int m; // m = month (3 = March, 4 = April, 5 = May, 6 = June, 7 = July, 8 = August, 9 = September, 10 = October, 11 = November, 12 = December, 13 = Janurary, 14 = February)
    int y; // Year ####
    //calculated values
    int k; // k = year of the century, last two digits.  For example, 2009 would be 09
    int j; // j = century (For example, in 1995 the century would be 19, even though it was the 20th century.)
    //After complet Calculations
    int h; // h = day of the week (0 = Saturday, 1 = Sunday, 2 = Monday, 3 = Tuesday, 4 = Wednesday, 5 = Thrusday, 6 = Friday)

    cout << "Enter the Day of the Month (1-31): ";
    cin >> q;
    cout << endl;
    cout << "Enter the Month: " << endl;
    cout << "3 = March, 4 = April, 5 = May, 6 = June, 7 = July, 8 = August, 9 = September, 10 = October, 11 = November, 12 = December, 13 = Janurary, 14 = February" << endl;
    cin >> m;
    cout << endl;
    cout << "Enter the Year: ";
    cin >> y;
    cout << endl;
    j = y /100;
    k = y % 100;
    h = (q + 26 * (m + 1) / 10 + k + k/4 + j/4 + 5*j) % 7;
    //  h = ( q + floor( ((m+1)26) / 10 ) + y + floor(y/4) + 6 * floor(y/100) + floor(y/400)) % 7;
    cout << h;
    system("pause");
    return 0;
}

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